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(II) The position of a rabbit along a straight tunnel as afunction of time is plotted in Fig. $36 .$ What is its instanta-neous velocity $(a)$ at $t=10.0 \mathrm{s}$ and $(b)$ at $t=30.0 \mathrm{s}$ ?What is its average velocity $(c)$ between $t=0$ and$t=5.0 \mathrm{s}, \quad(d)$ between $t=25.0 \mathrm{s}$ and $t=30.0 \mathrm{s},$ and$(e)$ between $t=40.0 \mathrm{s}$ and $t=50.0 \mathrm{s} ?$

a) $0.3 \mathrm{m} / \mathrm{s}$b) $1.2 \mathrm{m} / \mathrm{s}$c) $0.30 \mathrm{m} / \mathrm{s}$d) $1.4 \mathrm{m} / \mathrm{s}$e) $-0.95 \mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 2

Describing Motion: Kinematics in One Dimension

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

University of Washington

Simon Fraser University

University of Winnipeg

Lectures

03:28

Newton's Laws of Moti…

04:16

In mathematics, a proof is…

02:43

(II) The position of a rab…

06:50

02:31

A velocity-time graph for …

01:34

Figure $2-21$ is the posit…

02:40

A graph of $v(t)$ is shown…

02:41

A position-time graph for …

05:33

The velocity-versus-time g…

02:58

Figure $2-23$ shows the po…

00:32

Suppose $s(t)$ is the posi…

01:01

02:26

An object moves along the …

04:22

The velocity vs. time grap…

03:07

Figure $\mathrm{P} 2.16$ s…

02:30

(II) Suppose the position …

06:23

03:34

The position of a particle…

01:21

06:44

(1I) The position of a sma…

02:50

(II) The position of an ob…

03:36

Figure $\mathrm{P} 2.15$ s…

So here we have to interpret the graft and if you have slightly different answers, it's okay because again, wth igra half can be up to interpretation. So values that I'm able my may read Maybe, you know, one off once it gets a year off from, uh, the values that you're reading from the graph. But in general, we can say that for party to find the instantaneous velocity, we could say the instantaneous. This would be equal to the slope of the tangent line to the curve so we can save the instantaneous. AT T equals 10 seconds would be equal to three meters minus zero meters, divided by 10.0 seconds minus zero seconds. So this is giving us 00.3 meters per second now for part, the we have the instantaneous velocity at T equals 30 seconds, and here this would be equal to 22 meters, minus 10 meters, divided by 35 seconds minus 25 seconds. This is giving us a 1.2 meters per second and we can find C d. E for the average velocity, so the average velocity from zero seconds to five seconds would be equal to x at five minus x at zero, divided by five seconds, minus zero seconds. This is giving us 1.5 meters divided by 5.0 seconds, giving us 0.30 meters per second. Four part D. We want to find the average velocity from 25 seconds to 30 seconds. So this would be equal to X at 30 seconds, minus x at 25 seconds, divided by 30 seconds, minus 25. Let's do 30 0.0 seconds minus 25.0 seconds. And this is giving us Ah, 16 meters minus nine meters divided by, of course, 5.0 seconds. This is giving us 1.4 meters per second. And for perky. Finally, we have the average velocity from 40 seconds to 50 seconds. So again, X at 50 minus x at 40 divided by 50 seconds, minus 40 seconds. And so this is giving us 10 meters minus 19.5 meters and then we'll say, divided by, of course, 10 seconds. And this is giving us a negative 0.95 meters per second. That is the thank you for watching

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