Question
(II) The velocity of waves on a string is 96 $\mathrm{m} / \mathrm{s}$ . If the frequency of standing waves is 445 $\mathrm{Hz}$ , how far apart are the two adjacent nodes?
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This is because a full wave cycle consists of a crest and a trough, and the nodes are the points where the wave crosses the equilibrium position. Show more…
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(II) The velocity of waves on a string is 92 $\mathrm{m} / \mathrm{s}$ . If the frequency of standing waves is 475 $\mathrm{Hz}$ , how far apart are two adjacent nodes?
The speed of waves on a string is 97 m$/$s. If the frequency of standing waves is 475 Hz, how far apart are two adjacent nodes?
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