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(II) Two masses, $m_{\mathrm{A}}=35.0 \mathrm{kg}$ and $m_{\mathrm{B}}=38.0 \mathrm{kg},$ are connected by a rope that hangs over a pulley (as in Fig. $59 ) .$ The pulley is a uniform cylinder of radius 0.381 $\mathrm{m}$ and mass 3.1 $\mathrm{kg}$ . Initially $m_{\mathrm{A}}$ is on the ground and $m_{\mathrm{B}}$ rests 2.5 $\mathrm{m}$ above the ground. If the system is released, use conservation of energy to determine the speed of $m_{\mathrm{B}}$ just before it strikes the ground. Assume the pulley bearing is frictionless.

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1.4 $\mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 10

Rotational Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Simon Fraser University

University of Sheffield

McMaster University

Lectures

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

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(II) Two masses, $m_A = 32…

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(III) Two masses, $m_{1}=1…

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Two masses, mA = 33.0 kg a…

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Two masses, mA = 30.0 …

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Two masses, mA = 32.0 kg a…

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The two masses $\left(m_{1…

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A mass $m_{1}$ and a mass …

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Two Blocks on a Pulley In …

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The pulley in $\textbf{Fig…

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A $15.0-\mathrm{kg}$ mass …

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A 12.0-kg box resting on a…

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Initially the system of ma…

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$\bullet$ The pulley in Fi…

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Two masses are connected b…

so the angular speed of the police is related to the speed of the masses. We can say that Omega would be cooing V over r and so we can apply the conservation of energy Energy initial equals energy final. And we can then say that we know that all objects have an initial speed of zero. So we can say 1/2 amps of a V initial square. This would be the initial translational kinetic energy of Mass A plus the initial translational kinetic energy of mass be plus the initial rotational energy plus the initial gravitational potential energy plus the initial gravitational potential Energy of mass sub B Rather we can say ASAP to I and then here you can say why sub one hi. And this would be equaling essentially the exact same thing but final. So it would be 1/2 im someday The final squared plus 1/2 I'm so happy. The final squared plus 1/2 Iomega final squared plus M c A G. Why someone final? Plus I'm sub b g. Why some to final? And so we essentially find that mass. Have you thought over here Massa b g h would be equaling 1/2 m sub a. The final squared plus 1/2 Massa be the final squared plus 1/2 times 1/2 em r squared multiplied by the final over our quantity squared plus m sub a g h. And so we can say that the final would be equal to the square root of two times m sub B minus m sub a times G h. This would be divided by M sub a plus m sabi, plus 1/2 times the mass of the pulley. And so we can then solve the final velocity would be equaling the square root. I have monitor two times 38.0 minus 35.0 kilograms multiplied by 9.80 meters per second squared multiplied by 2.5 meters. And then this would be divided by essentially a 38.0 plus 35.0 plus 1/2 times 3.1. The units are of course kilograms. This is equaling 1.4 meters per second. This would be our final answer for the final velocity. That is the end of the solution. Thank you for

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