00:01
In this problem, on the topic of newton's laws of motion, we are told that two snow cats are being used to tow a housing unit, u -north.
00:09
The sum of the forces, as we can see in diagram, f -a and fb, exerted on the unit by the horizontal cables, is north and is parallel to the line l.
00:19
If we are given the magnitude of f -a to be 4 ,500 newton's, we want to find the magnitude of fb and the magnitude of f -a -plus f -b.
00:30
So we'll choose the y direction to be forward for the motion of the snow cats, since that coincides with the north, and x to be to the right on the diagram as it is in the textbook.
00:43
So since the housing unit moves in the forward direction on a straight line, there's no acceleration in the x direction.
00:48
And so the net force in the x direction has to be zero.
00:53
So writing the equation for newton's law along the horizontal direction, we have the resultant force in the x direction must be the sum of that due to force a plus the x component of the force b and this must be a total of zero so using some geometry this is the horizontal component of a f a sign of forty eight degrees minus f a sign of forty eight degrees plus f b sign of thirty degrees and this must equal to 0, which means from here that since we know f .a, we can rearrange and solve for fb...