(II) What average force is required to stop a 950-kg car in 8.0 s if the car is traveling at 95 km/h?

Answer

-3134N

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Physics 101 Mechanics

Physics

Chapter 4

DYNAMICS: NEWTON'S LAWS OF MOTION

Section 4

Newton's Second Law of Motion

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Video Transcript

So we need the average forced to stop this car. We have a mass of nine hundred and fifty kilograms and then we have a delta t equaling eight point zero seconds and we have a velocity initial equally, ninety five kilometers per hour. We need to convert two meters per second. So we have a thousand meters for every kilometer island for every one hour there are thirty six hundred seconds and this is giving us twenty six point three eight nine meters per second. We confined our average acceleration by taking velocity final. Mona's falsely initial over Delta T. We know that the final velocity is going to be zero because we're trying to stop this car. So the average acceleration was simply equal Native velocity initial divided by identity. So the force average is simply going to be equal to em. The mass times the acceleration average and this is going to equal negative and the initial divided by thousand eighteen. So this will be negative and and masses nine hundred fifty Time's a lost city initial twenty six point three eight nine and then divided by Delta t of a point zero. And we're getting a average force equaling negative because we're trying to stop the car. Three thousand one hundred thirty foreign dunes. So this will be our final answer. The force needed in order to stop the car in eight seconds. That is the end of the solution. Thank you for watching.

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