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(II) What average force is required to stop a $950-\mathrm{kg}$ car in8.0 $\mathrm{s}$ if the car is traveling at 95 $\mathrm{km} / \mathrm{h} ?$

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Physics 101 Mechanics

Chapter 4

Dynamics: Newton's Laws of Motion

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Moment, Impulse, and Collisions

Simon Fraser University

Hope College

University of Winnipeg

McMaster University

Lectures

03:28

Newton's Laws of Motion are three physical laws that, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces. These three laws have been expressed in several ways, over nearly three centuries, and can be summarised as follows: In his 1687 "Philosophiæ Naturalis Principia Mathematica" ("Mathematical Principles of Natural Philosophy"), Isaac Newton set out three laws of motion. The first law defines the force F, the second law defines the mass m, and the third law defines the acceleration a. The first law states that if the net force acting upon a body is zero, its velocity will not change; the second law states that the acceleration of a body is proportional to the net force acting upon it, and the third law states that for every action there is an equal and opposite reaction.

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

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(II) What average force is…

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What average force is requ…

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(a) What force is required…

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(II) If a car generates 18…

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Find the average force nee…

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A $1500-\mathrm{kg}$ car h…

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What force is required to …

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Starting from rest, a $940…

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(a) Calculate the force ne…

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Starting from rest and und…

the average force, so we should first find an average average acceleration. We know that the final velocity is zero meters per second and that the initial velocity is 95 kilometers per hour. However, we must convert this two meters per second. So we'll say 1000 meters rather 95 kilometers per hour, multiplied by 1000 meters per every kilometer and then multiplied by one hour for every 3600 seconds. And so the initial velocity is going to be equal to 26.4 meters per second. To find the average acceleration, we can use Kinnah matics so this would be the final minus the initial divided by Delta t we know it would be final is again zero. So this would be negative 26.4 meters per second, divided by in this case, 8.0 seconds. So this is giving us a negative 3.30 meters per second squared, um, to find the average force. This would simply be equal to the mass times acceleration average and this would be equal to 950 kilograms multiplied by again negative 3.30 meters per second squared the average forces found to be negative. My party negatives. 3.1 times 10 to the third Nunes. And this will be the final answer again. This is negative because this is in the opposite direction of the initial velocity, which we consider to be positive. In this case, that is tthe e end of the solution. Thank you for watching.

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