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(II) What is the normal pressure of the atmosphere at thesummit of Mt. Everest, 8850 $\mathrm{m}$ above sea level?

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$$3.35 \times 10^{4} \mathrm{N} / \mathrm{m}^{2}$$

Physics 101 Mechanics

Chapter 13

Fluids

Fluid Mechanics

University of Michigan - Ann Arbor

Simon Fraser University

University of Winnipeg

Lectures

03:45

In physics, a fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases, plasmas and, to some extent, plastic solids.

09:49

A fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases and plasmas. Fluids display properties such as flow, pressure, and tension, which can be described with a fluid model. For example, liquids form a surface which exerts a force on other objects in contact with it, and is the basis for the forces of capillarity and cohesion. Fluids are a continuum (or "continuous" in some sense) which means that they cannot be strictly separated into separate pieces. However, there are theoretical limits to the divisibility of fluids. Fluids are in contrast to solids, which are able to sustain a shear stress with no tendency to continue deforming.

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Mount Everest is 8850 mete…

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What is the atmospheric pr…

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The atmospheric pressure o…

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The decpest point in the o…

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Mountain Climbing The pres…

05:43

The typical atmospheric pr…

02:34

The deepest point in the o…

03:43

Atmospheric pressure The p…

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The pressure on top of Mou…

So we're going to use the relationship, developed an example 13 5 and we can say that the pressure would be equal in the atmospheric pressure times, the exponential function of the negatives and density times G over the atmospheric pressure. And then this should be multiplied by why and so we can solve. So this would be equaling 1.13 times 10 to the fifth Pascal's on, then multiplied by the exponential function of this would be negative one point to five times 10 to the negative forth per meter divided by or rather, my apologies multiplied by why 8850 meters. And so we find that the pressure would be equaling 3.35 times, 10 to the fourth Pascal's and converting toe atmospheres. We find the pressure is approximately equal toe 0.331 atmospheres. This would be our final answer in atmospheres and our final answer in Pascal's that is the end of the solution. Thank you for watching

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