Question
(II) What volume of water at $0^{\circ} \mathrm{C}$ can a freezer make intoice cubes in 1.0 $\mathrm{h}$ , if the coefficient of performance of thecooling unit is 7.0 and the power input is 1.2 kilowatt?
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Mathematically, this can be expressed as: \[ COP = \frac{Q}{W} \] where \(Q\) is the heat removed and \(W\) is the work done. Show more…
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(II) What volume of water at $0^{\circ} \mathrm{C}$ can a freezer make into ice cubes in 1.0 hour, if the coefficient of performance of the cooling unit is 7.0 and the power input is 1.0 kilowatt?
(II) What volume of water at 0$^\circ$C can a freezer make into ice cubes in 1.0 h, if the coefficient of performance of the cooling unit is 6.0 and the power input is 1.2 kilowatt?
THE LAWS OF THERMODYNAMICS
Refrigerators, Air Conditioners, and Heat Pumps
An industrial freezer operates between $0^{\circ} \mathrm{C}$ and $32^{\circ} \mathrm{C},$ consuming electrical energy at the rate of $12 \mathrm{kW}$. Assuming the freezer is perfectly reversible, (a) what's its COP? (b) How much water at $0^{\circ} \mathrm{C}$ can it freeze in 1 hour?
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