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(II) When different masses are suspended from a spring, the spring stretches by different amounts as shown in the Table below. Masses are $\pm 1.0$ gram. $\begin{array} { l } { \text { Mass (g) } 0 } & { 50 \quad 100 \quad 150 \quad 200 \quad 250 \quad 300 \quad 350 \quad 400 } \\ { \text { Stretch } ( \mathrm { cm } ) 0 \quad 5.0 \quad 9.8 \quad 14.8 \quad 19.4 \quad 24.5 \quad 29.6 \quad 34.1 \quad 39.2 } \\ \hline \end{array}$ (a) Graph the applied force (in Newtons) versus the stretch (in meters) of the spring, and determine the best-fit straight line. (b) Determine the spring constant $( \mathrm { N } / \mathrm { m } )$ of the spring from the slope of the best-fit line. (c) If the spring is stretched by $20.0 \mathrm { cm } ,$ estimate the force acting on the spring using the best-fit line.

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$$=[2.00 \mathrm{N}]$$

Physics 101 Mechanics

Chapter 7

Work and Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Hope College

University of Sheffield

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

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When different weights are…

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After a mass $m$ is attach…

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09:57

A certain spring is found …

7.93. So we have, ah, table of some data here. Uh, that comes from placing masses on a spring and measuring how much the spring stretches. So the first thing we want to do is grab the force that's being applied to the spring by these masses versus the stretch, Um, so and then finding a best fit line, et cetera. So to do this, you first want to. It tells us we want f in Newton's index and meters, So comfort the centimeters here, two meters, then convert three grams here, two kilograms and then multiplied by 9.8 meters per seconds squared. And so then putting this into excel or something, you get a plot that looks like this. So here is our best fit line, which we will copy down back over here so you can see that our spring constant is going to be because the just the intercept here is zero ends using the correct number of, uh, significant digits. It works out to be 10 actually, 10.0. So our spring constant then is just 10.0 newtons per meter and, uh, so using our best fit line here. We want to find the force when it's that we stretch the spring 20 centimeters, which you could see is not a value that we have here. This is K Times X, so that's head Newtons per meter. I'm 0.2 meters and so we get a force of two Newton's.

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