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(III) A 3.0 -kg block sits on top of a $5.0-\mathrm{kg}$ block which is ona horizontal surface. The 5.0 -kg block is pulled to the rightwith a force $\vec{\mathbf{F}}$ as shown in Fig. $39 .$ The coefficient of staticfriction between all surfaces is 0.60 and the kinetic coeffi-cient is $0.40 .$ (a) What is the minimum value of $F$ needed tomove the two blocks? (b) If the force is 10$\%$ greater thanyour answer for $(a),$ what is the acceleration of each block?

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a. 82.41$N$b. $4.464 m / s^2$

Physics 101 Mechanics

Chapter 5

Using Newton's Laws: Friction, Circular Motion, Drag Forces

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

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Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

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Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

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In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

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31. (II) A 3.0-kg block si…

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4. A 3.0-kg block sits on …

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{(0.02) (a) Find the accel…

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(III) A 4.0 -kg block is s…

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A 2.00-kg block is placed …

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Block $B$ has mass $5.00 \…

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(III) Three blocks on a fr…

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Three blocks are in contac…

07:09

In Fig. 6-35, block A of m…

02:49

A $2.5 \mathrm{~kg}$ block…

10:09

A $5.00-\mathrm{kg}$ block…

07:37

07:15

Three blocks of mass $m_{1…

06:03

(II) Three blocks on a fri…

04:25

ao A $2.5 \mathrm{~kg}$ bl…

my friends, This is a problem. Based on Newton's second up here it is given two blocks A and B having the must three kiddies and fight creating are connected by the district and arranged has surrendered figure given coefficient of friction between the surfaces while six aesthetic and theoretic. It's quite food. B block is full towards right by the force f part of In the first part, we have to calculate the minimum force by with B block is to be pulled so that blocks starts moving. Okay, If applied force is to be increased to bite 10% then find acceleration off the blocks. First, we have to drug a free body diagram. Everybody off block eight wait off the block will like toward agreed onward normal direction and a and upper direction Danger in this 20 in this direction and a friction static a V in this direction. So here and it will be equal toe. I am in too deep. And if it is moving towards left big expiration in for just start, it will be zero so you can write to you minus her face A B. It's very toe moss in tow. Acceleration Oh, friction will be us. I am a and two G. It's called Ozio. That s t's called Tow us. I am a into G every day. Off and blobby. Yeah, this is the B block. Wait off the block. Reaction off a reaction off B Yeah. Force pension friction. Aesthetic A V friction aesthetic between the block B and surface friction. Aesthetic A V is Mu s m a into G friction aesthetic B and surface mu s. I am a into G plus. I am being too g. That is M s m e plus m being duty. Yeah, if it is tending to move towards right, acceleration is zero. So equation all forcible. We have minus t friction between a V friction between surface and be his call to zero so it can be written us Mewes. Yeah, I am a into G um us Ami. Plus I'm being duty must be true from equation too. Well, for Yeah, Baloo off f We will find, um us into three m eight plus m b and two G. Yeah. Yeah, us is 16 three and 23 But let's fight and to 9.8. So it is 82 point three to Newton. This is the answer off party. No party if force to be increased by 10% off F, that is 82.32 plus 10 500 Oh, a tickle paltry toe. So place becomes 90.5 Newton in this case equation or force for Block A and blocked me four block eight. It will be do u minus u S m a into G. It's good toe a into a on four block B. This is for eight on four block B. We can write. Have minus T u s am into ji. This is every century members Mm egg plus m being duty. His per to have been to a solving equations five and six people solving equations five and 6 ft acceleration. I'm writing here directly. It would be Have this minus Mu Qing. This is Mucha. Let me correct you. This will be mute. Okay, because the system it start moving mu key three m a less MB upon I am a less and be substituting the world 19.5 while four 323 plus pipe in two 9.8 less three plus five toe on solving it acceleration. We will get 4.459 meter per second square. That's all. Thanks for watching it. Yeah.

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