Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

(III) A beaker of liquid accelerates from rest, on a horizontal surface, with acceleration $a$ to the right. (a) Show that the surface of the liquid makes an angle $\theta=\tan ^{-1}(a / g)$ withthe horizontal. (b) Which edge of the water surface is higher? (c) How does the pressure vary with depth below the surface?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

a) $\theta=\tan ^{-1}\left(\frac{a}{g}\right)$b) The left edge of the water surface, opposite to the direction of the acceleration, will be higher.c) $$P=P_{0}+\rho h g$$

Physics 101 Mechanics

Chapter 13

Fluids

Fluid Mechanics

University of Michigan - Ann Arbor

University of Washington

Simon Fraser University

University of Winnipeg

Lectures

03:45

In physics, a fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases, plasmas and, to some extent, plastic solids.

09:49

A fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases and plasmas. Fluids display properties such as flow, pressure, and tension, which can be described with a fluid model. For example, liquids form a surface which exerts a force on other objects in contact with it, and is the basis for the forces of capillarity and cohesion. Fluids are a continuum (or "continuous" in some sense) which means that they cannot be strictly separated into separate pieces. However, there are theoretical limits to the divisibility of fluids. Fluids are in contrast to solids, which are able to sustain a shear stress with no tendency to continue deforming.

02:59

On a horizontal surface, a…

01:08

An open vessel containing …

01:05

(III) A common effect of s…

03:02

A vessel containing water …

07:59

A rectangular box containi…

01:38

Pressure at a point inside…

03:48

IP A pan half-filled with …

02:19

The pressure at the bottom…

02:02

A vessel containing water…

02:00

A vessel of water is place…

03:15

Three liquids having densi…

So here, equities the diagram. You can tell that here the effective acceleration would be denoted by ah g prime. And according to the vectors, this is gonna be equal to the acceleration vector. Rather be the gravitational acceleration vector plus the acceleration factor. Therefore, we know that tan. Sorry, it data rather is gonna be equal to Arc Tanne of a divided by G. It's that would be the final answer for part rather us proving of port, eh? And then, for part B, we know that the left edge of the water surface again opposite to the direction of acceleration will be higher. So I would be your answer for part B and then for part c ah, they want us to find the pressure. So here, um, we know that h prime would be equal to h co sign of Fada. And so we can say that P is going to be equal to the atmospheric pressure plus the gauge pressure. So the density times gravity brother times, Deeks, Effective acceleration, G prime times h prime. And, uh, this is P will be equal to p, not the atmospheric pressure, plus the density times the square root of G squared plus a squared and then multiplied by h co sign if Ada And so we find that pee is gonna equal p not plus P g h again. As you can see, this is gonna be the same as the UN accelerated case. So this would be our final answer. That is the end of the solution. Thank you for watching.

View More Answers From This Book

Find Another Textbook

07:03

A charge of -3.33 C is fixed at the center of a compass. Two additional char…

03:03

The velocity-time graph for motion of two bodies A and B is as shown. Read t…