Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

(III) A huge balloon and its gondola, of mass $M,$ are in the air and stationary with respect to the ground. A passenger, of mass $m,$ then climbs out and slides down a rope with speed $v,$ measured with respect to the balloon. With what speed and direction (relative to Earth) does the balloon then move? What happens if the passenger stops?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

$v_{\mathrm{BG}}=v \frac{m}{m+M},$ upwardthe balloon also stops

Physics 101 Mechanics

Chapter 9

Linear Momentum

Motion Along a Straight Line

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

Cornell University

University of Michigan - Ann Arbor

Simon Fraser University

McMaster University

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

05:22

(III) A helium balloon and…

03:14

(III) A huge balloon and i…

02:44

A man of mass $m$ climbs a…

01:30

A balloon of mass M is flo…

01:45

A man of mass $m$ clings t…

01:54

A man of mass $m$ stands o…

06:03

$\bullet$$\bullet$$\bullet…

02:16

Terminal speed of balloon …

06:24

The force of buoyancy exer…

01:37

A balloon of mass $m$ drif…

03:15

an $80 \mathrm{~kg}$ man i…

02:33

A hot-air balloon consists…

02:46

A hot-air balloon of mass …

A balloon with mass $M$ is…

01:34

A balloon with mass $m$ is…

Okay, so we're doing Chapter nine problems. 70 here says the huge balloon in its gondola have a mass big in our air stationery with respect to the ground. There's a passenger fast little end which climbs out and slides down a rope at a speed the measured with perspective. But Bolin, what speed and direction wrote Earth does the balloon then move? Okay, so if we call the origin of the coordinates the center of mass of the balloon in the gondola and person at rest. Since the center of Mass is at rest, the total momentum of system fell to the ground zero. This is important. So we need that Total moment zero and the man climbing the rope cannot change the total system since he's in the system. So we call upwards positive. Why downwards Negative y such This is our coordinate system. We know that velocity of Maine is a good fee because he's moving at the speed you could. So that means the velocity refer. Expect philosophy of man with respect to the ground. Give it as the velocity of the balloon, expect to the ground minus beaten. So we know this relation now and We also know that the total moment must be zero. So zero then must be equal to end times the philosophy of the man suspected ground. Plus, then comes the velocity use. Sorry, this is big in times the velocity of the bloom respectively. So now let's talk. Listen, when we see that, then times the G but its feet because big Oh, sorry. Plus again D d g called zero So we can solve this. So the velocity of the blue perspective ground now given as be a little in over little plus big, huh? Cool. This is also gonna be upwards because it's positive as we see.

View More Answers From This Book

Find Another Textbook

01:10

atwood machine An Atwood Machine is basic physics laboratory device ofte…