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(III) Show that inside a soap bubble, there must be a pressure $\Delta P$ in excess of that outside equal to $\Delta P=4 \gamma / r,$ where $r$ is the radius of the bubble and $\gamma$ is the surface tension. [Hint: Think of the bubble as two hemispheres in contact with each other; and remember that there are two surfaces to the bubble. Note that this result applies to any kind of membrane, where 2$\gamma$ is the tension per unit length in that membrane.

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$\frac{4 \gamma}{r}$

Physics 101 Mechanics

Chapter 13

Fluids

Fluid Mechanics

University of Michigan - Ann Arbor

University of Washington

Simon Fraser University

University of Sheffield

Lectures

03:45

In physics, a fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases, plasmas and, to some extent, plastic solids.

09:49

A fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases and plasmas. Fluids display properties such as flow, pressure, and tension, which can be described with a fluid model. For example, liquids form a surface which exerts a force on other objects in contact with it, and is the basis for the forces of capillarity and cohesion. Fluids are a continuum (or "continuous" in some sense) which means that they cannot be strictly separated into separate pieces. However, there are theoretical limits to the divisibility of fluids. Fluids are in contrast to solids, which are able to sustain a shear stress with no tendency to continue deforming.

02:04

Under isothermal condition…

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When heat is given to a so…

01:18

The radii of two soap bubb…

02:00

Suppose the radius of the …

So as you can see here, we only have half of the soap bubble. So essentially two times the force tension would be equal to the Force Force A Pete. Ah, we can say that two times two pi r times the surface tension would be equal to pi r squared times the change in pressure. Ah. Therefore the change in pressure is going to be equal to four times the surface tension on divided by our And this would be our final answer. That is the end of the solution. Thank you for watching.

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