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6 .47.
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So we want to use the table that's given earlier in the problem set of the periods and mean orbital distances of the four largest moons of jupiter.
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And so we want to, first we want to take kepler's law in this form and show that if we plot the logarithm of the period of each moon against the logarithm of its mean orbital distance, we want to show that this will give us a straight line and then talk about what the slope and y intercepted that line mean, or r at least.
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And then we want to plot this and figure out the mass of jupiter based on that.
00:46
So to begin with, we just take the logarithm of both sides here, where m sub capital j is the mass of jupiter.
01:29
Oh, wait not on part b yet.
01:31
So, just using the properties of logarithms, we'll see that this is 2 times log t, and this is the logarithm of a product, which is going to be the sum of the logarithms.
01:55
And then also we'll get a 3 down from our log r cube.
02:04
So we have 3 log r plus log of 4 pi squared over gmj.
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And then if we just divide both sides by two, we get log t, which is sort of our y equals three halves log r.
02:46
So this is going to be our slope times x.
02:52
So this is the slope of the line will be three halves, plus one half times the log of four pi squared over gmj.
03:36
So this is good.
03:38
So if we plot log of t versus log of r, we know what the slope should be.
03:44
And then we also know that we can find the mass of jupiter from the y intercept...