00:02
All right, let's consider a scenario in which we have two variations, isotopes, two flavors, hydrogen.
00:15
The first one we'll just call hydrogen.
00:18
The other one called, i might be butchering this pronunciation here, but deuterium.
00:33
Okay, so if both of the temperatures are equal, which can we expect to have a greater kinetic energy? so you might recall a kinetic energy can be evaluated using 3 over 2, ultimate constant, two times temperature, equal to the relationship can be determined experimentally because temperature is directly proportional to the speed of the particles in the gas.
01:13
So i do not expect that either of them have greater kinetic energy.
01:28
And moving on, which diffuses fast.
01:34
At a given temperature.
01:38
So we can also solve for kinetic energy using this expression right here.
01:52
We know that the kinetic energy is equal because the temperature is equal.
01:58
So we would expect this expression to be true.
02:12
Say we, okay, say for hydrogen, we have a decrease in mass or it's decreased relative to deuterium.
02:25
However, if this were to happen and for this relationship to hold for any given set of atoms, particles, excuse me, i'd expect the velocity of hydrogen also need to increase to break even with the kinetic energy of deuterium.
02:44
So, i'd expect hydrogen uses faster.
02:56
It's a strange looking at.
03:07
My sloppy cursive, much better.
03:11
All right.
03:14
So we're given a problem in which...