00:02
So here we're looking to replace the hydrogen atom on the methane group, which will change the symmetry and the structure of the compound.
00:09
And so this will change the interactions of the properties.
00:14
So with methane, what we have is a ch4.
00:19
So this is tetrahedral geometry and so we only have dispersion forces because it lacks a dipole moment.
00:25
So that's why it does have a very low boiling point.
00:28
If we replace a hydrogen with a fluorine, then what we generate is c.
00:36
So what we get is ch3f.
00:43
This is not a symmetrical compound anymore because of the polar fluorine that is associated to carbon.
00:51
So we have an overall dipole present.
00:54
And so because we have a dipole, now we can have dipole dipole dipoles forces rather than just dispersion forces.
01:00
That was present with ch4...