imagine-that-you-want-to-measure-two-red-solutions-to-determine-if-they-have-the-same-concentratio-2

Question

Imagine that you want to measure two red solutions to determine if they have the same concentration of red dye or not.
a. What type of light source do you need for the spectrometer?
b. Sketch the placement of the light source, the detector, and the sample. Show the path of the light.
c. What do you predict you will observe if the two solutions are different?
d. Can you use UV-sensitive paper for the detector? Why or why not?

Madi Sousa · Accepted Answer

This is a great problem from your textbook because this describes something a chemist or a spectroscope ist might do in the lab where we have two solutions and we have to distinguish between them. We have to find the differences between them in order to use them either together or separately. So the first that we can dio is that to find the concentration of the solution, we would use UV light so we can definitely use UV light as as our source of radiation. And then what we would do is we will put our sample into a spectrometer and we&#x27;re told to simply draw the components or the spectrometer itself. So in a spectrometer, what we have is a source of electromagnetic radiation. So in this case, we would use something like UV light or UV lamp, and we would have a essentially a place to shine that light into an entrance slit. So a very small, specific, centered place for that like to go through. And then we&#x27;d have some sort of device to separate the wavelengths of our solution, which in this case, something like a prism. Then we&#x27;d have an exit slit and notice here how Onley once very specific wavelength of color comes out of that entrance or party that exit slit. And that&#x27;s the wavelength of light that would hit our sample and then our light detector to see our spectra. Now in the lab, you probably won&#x27;t see all of these different components. You would have a machine that contains different things that would do all of these different things, but we wouldn&#x27;t see them individually, but they would still see a spectrum. This is the principle of a spectrometer. So for see if we have two different solutions and we want to distinguish them, the two different solutions would ideally have two different shades of color on UV paper. And that&#x27;s one way to distinguish them. And then also, the last question asks us, Can we even use UV paper to distinguish our solutions? And the answer is yes. The solutions of different concentration will show different color because the concentration could have more electrons to absorb energy, and we would definitely be able to use UV paper

Alex Moore · Answer

Okay, This is a fun question. So we should know that red light the wavelength of red like is around 700 nanometers, Give or take, the wavelength of violet light is around 400 nanometers. Give or take. Now, for all electromagnetic wavelength, the speed of that radiation is equal to its frequency times its wavelengths. This means that frequency is equal to speed of light or the speed of the radiation, which is a constant over its wavelength. Okay, so that means that frequency and wavelength are inversely related. So if a wavelength is bigger, then the frequency is smaller, okay? And since red, like, has a bigger wavelengths, red light has to have compared to violet light. That means that the frequency of red light is smaller than the frequency violet light. Okay, so first thing we should know is that violet Light has a larger frequency because it has a smaller wavelength. Okay. And next part of our question is going to calculate the frequency of blue light and calculate the frequency of red light. All right. And just like before we know that frequency is equal to the electromagnetic radiation speed over its wavelength. Okay, So for blue, we want to know the frequency that&#x27;s going to be C, which is three times 10 to the eighth meters per second over its wavelength, which is 470 nanometers. Nano means 10 to the minus nine meters. Okay, so the frequency of blue light is three times 10 to the eighth over 470 times 10 to the minus ninth. That&#x27;s 6.37 times 10 to the 14th. Okay. And that&#x27;s in units of one over second, which means hurts. Okay, so that&#x27;s four blue light. And now for a red light, you do the same thing. All right. Red light is three times 10 to the eighth meters per second. It travels at the same speed, divided by 600 and 80 nanometers, which is 680 times 10 to the minus. Ninth meters, right meters. Cancel. We&#x27;re gonna be left with three times E to the eighth, divided by 6 80 times 10 to the minus ninth. It&#x27;s gonna be four point for one times 10 to the 14th. 14th hurts. Okay, so that&#x27;s the frequency of red. Like that&#x27;s the frequency of blue

Md Mohibullah · Answer

so we know that a color solution basically observed light more strongly in the region. Off tips, complimentary color. So, for example, if a solution is a blue color, then it will observe light in is your own, which is a complimentary tow. This blue color solar see from our textbook, which color which vision is compliment rate or blue color. So from here you can see that the orange region is complimentary to our blue color. That means a blue color solution well observed most strongly in the orange coloration, which is Ah Web Lin Trajan off five eighteen Animator Tto six fifteen An emitter, some in case a blue solution. The color. Observe these orange and the weapon is five hundred eighteen. Animator Fool six hundred fifteen Animator than intense off red F C. What is the complimentary color of Fred? So from here, you can see that green is the complimentary color of friend segments. Red color Solution Will will observe a light more strongly in the Green region and in the Web. Land off four hundred ninety generator to five hundred sixty millimeter. It&#x27;LL absorb green light within the Webley and range of four hundred nineteen and a meter two five hundred sixty nine meter and then a year local. Our solution will observe light in violet or purple region or purple coloration. And on the Web land risen, limited way from four hundred nanometer toe for thirteen. An emitter. So yeah. Look, Honor solution will observe you file a flight. Ah, violet color and the weapons limit will be four hundred nine o meter tow for thirteen and a meter.

Zulfiqar Ali · Answer

volatile friend. Bull uh, bottle red bulb equals 1 50 walks 1 50 watts and a power of blue bull a blue boat equals equals 40 more 40. What on DDE that Linda off red light Bab lint off red light Because ah, 6 48 centimeters, which is 6 40 Multiply by 10 to the power minus nine meters and Lapland off blue light, uh, equals for turning animators. And it&#x27;s equal to 4 30 Multiply by a 10 to the dollar minus mind meters Um, red light, but red light boned equals 1 50 joules per second s a bower of red light. Bold Oh, power off red light. Ah, boat uh equals one 50 boards 1 50 bought is 1 50 Jules for a second. And then it&#x27;s your friend Lightfoot on. He&#x27;s given by e equals HC, divided by Lambda. Let&#x27;s up. Plug in the values Ages 6.63 Multiply by 10 to the power minus 34 multiplied by C is three multiply by 10 to the power it divided by Linda off red light is 6 40 Multiply by time to the power minus nine and this gives us 3.1 multiplied by Dante Power minus 19 Jules. So e equals 3.1, multiplied by 10 to the power minus 19. Jules, now a number of stones immediate by red Bold per second number, number or four dawns Number of photons emitted by red, bold and make did. Bye. Red boat Red, Bold per second. Where second equals 1 50 Divided by 3.13 point one. Multiply by identity baller minus 19. Dividing the numbers, we have four point it multiply by stand to the power 20 four dawns 24 tones and similarly power off blue light bulb. A power of blue light bulb blue light book uh equals 40 watt which which is 42 for a second and energy off Blue light is given by e equals etc. Divided by Lander Landes, reverent of blue light and putting the values we have 6.63 multiplied by 10 to the power minus 34 multiplied by C is three multiply by 10 to the power it divided by lander In this case is four party multiply by 10 to the power minus 94 30 multiplied by 10 to the power minus mine and solving this. We get equals. Energy equals 4.6. Multiply by 10 to the power minus 19. Jules minus 19 Jules A number of photons emitted by blue boat per second number off for dawns number off What dawns Emitted by blue Bold emitted Bye Blue Boat Blue Bold per second for a second equals 40 divided by 40 Divided by 4.6. Multiply by 10 to the power minus 19 and this abuses 8.7 multiplied by 10 to the power 19 four dawns 19 4 tones. So, uh, the answer to part a is a red boat emits more photons than blue ball. Uh, red emits more for Don&#x27;s right boat emits more for tones. More four tones UH, four tones and Barbie blue light for dawn has more energy. The answer to part is, Ah, blue light foot on blue light put on has more energy, has more energy

Shital Rijal · Answer

Okay, so here, really light off woodland Lambda That light over number are is equality 700 nanometers This blast plasterers to sit apart. Us now at the same time another monochromatic lettuce past. It is considered that to be Lambda. We&#x27;re going to flight? No, it was seeing that center of third of Brad things at your spear. Right? So that means that the that mention that particulate position, the real light lambda are went on to have constructive interference, whereas Lambda went on to have destructive interference. Give me that. That here is that party could appoint where it was read under our underwent giving your furnace. Whereas Lambda truant destructive interference. That&#x27;s where we can see Pierre, right? So for that person, if that reconsidered that be why Why should be called three times Landa are Di Vita, where Capital D is the distance between that chair, So just dance between stage and screen, all right? Small d sleater spacing. But so this is for the red light and at the same point by their destructive indifference Do too I&#x27;m not for destructive difference you, em and the South. Bye. All right, so from this two questions What we can&#x27;t figure out is that from these three questions, right and plus half off Lambda should be cordial freedoms that death Toll bridge, right? So then by quotes true three horn on us. How off, Remember? So this John Bytom the values for Chemical zero gifts Lambda quotes, too. We&#x27;ll be under that. Impressed with this is not a busy reason. We need events. Invisible reason. So let&#x27;s move on. But every one Namdar victims 1400 then just okay, it is decreasing. I&#x27;m going to Lambda equals two heat forgiven odors. See that it&#x27;s to prison now me reach There is a reason three them that comes out of the 600 you know? So we have greased There&#x27;s your reason. And Mrs one weapon smoothly for any good before Lambda equals two for 66 by 66 Well, this is also it&#x27;s also lives in terrorism. Right, So this move on fire number I posted 3211 Katie test No. Went out of his real reason. So these are two possible reverends off second, right? Right. No. Do you need to know the city? Well? Do you reuse anywhere the band off? Do You know, Dick, it&#x27;s cancelled out when you saw this because right. So that you&#x27;re No, we don&#x27;t need it on gifts. Go, go! Oh, as you seem, Father, Resonance. Hence the sense. The solution for this question. Thank you for watching.

Mary Shields · Answer

all right, if you use a spectra for Tom Attar and the solution appears bread So in this case, we&#x27;re dealing with cobalt and we&#x27;re seeing a red solution, right? So spectre of fate ometer works by reading light, absorb ints. Okay, so if a solution is appearing bread, that&#x27;s because it&#x27;s transmitting red light. Okay, so that amount of light it&#x27;s not gonna change when it&#x27;s diluted. So things that we can measure that will change will be transmiten and absorb INTs. Okay, but for a red color, Okay, that&#x27;s just means that the distance between the energy levels in that cobalt ion, um, are associated with that. That red color of light in terms of the wavelength, eh? So we&#x27;re looking at the electron transitions within the cobalt ion.

Problem

What differences do you predict if you use UV-sen…

Problem 6 Easy Difficulty

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