00:01
So first let's write down the known information.
00:04
So we know the mass of each bag, let's call that mb, and that's given to be 10 to the power minus 3 kgs.
00:16
And we also know the gravitational constant.
00:19
That's equal to 6 .67 times 10 to the power minus 11 newton times meter square over.
00:30
Kg square and this gravitational constant are we are going to use this further in this problem and we are given that one bag is at the north pole of earth and the other one is at the south pole so we can find the distance between the two bags and that will be equal to twice of the radius of the earth where the radius of the earth is 6 .3.
01:03
6 .371 times 10 to the power 6 meter.
01:09
So that's the radius of the earth.
01:11
So using that we can find the distance between the two backs.
01:16
Now in the first part we have to find the number of protons in each bag.
01:24
So we know that mp the mass of the proton is equal to 1 .67 times 10 to the part.
01:34
Minus 27 kg so this is the mass of one single proton therefore nb will be equal to number of protons inside each bag times mass of the proton so from here we can find n which will be equal to mb the mass of each back over mass of each proton and that will give us 6 times 10 to the power 23 after substituting the values.
02:07
So this is the number of protons in each pack.
02:17
So that's the first part.
02:19
Now in the second part, we have to find the electric force and gravitational force.
02:27
So the electric force is given by 1 over 1.
02:35
4 pi epsilon 0 square of like multiplication of all the charges of both the charges of the two bags over square of the distance between them that is d and here since both the charges are equal so because they have the same number of protons so this will then be equal to q square where q is the amount of charge in each back over d square and let's write this factor one 4x0 as k...