00:01
In this question we have got the position of rock falling from cliff has a function of time and that is given as position.
00:12
So that is s of t as equals to 16 t square.
00:18
Okay.
00:19
So the first question they asked when the rock will hit the ground, okay? and the height of the cliff is, height of the cliff is 96 feet.
00:37
So for the first question we have to find the time when this rock which is falling from the cliff will hit the ground.
00:46
So essentially for that what we will be doing is the position function is given as s of t.
00:51
So we will equate the position function with height of the cliff and we'll get the time.
00:57
So in this case 96 will be equals to 16 t square.
01:03
Okay, 16, 6xia, 96 and then.
01:08
And if we calculate it to t we are getting is root of 6 seconds.
01:14
Okay, so the rock will hit the ground at the time t is equal to root 6 seconds and that is answer for the part a.
01:23
In part b, we have to calculate the speed or the velocity of the rock when it hits the ground.
01:34
So, for that what we will be doing is we will differentiate this function of position.
01:39
So t squared, so velocity will be equals to or d s by d t.
01:46
So what will be getting? we will be getting 32t.
01:51
Okay? and the time we already have, time is root 6...