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In $12-23,$ each set is a function from set $A$ to set $B .$ a. What is the largest subset of the real numbers that can be set $A$ , the domain of the given function? b. If set $A=\operatorname{set} B,$ is the function onto? Justify your answer. $$\{(x, y) : y=\sqrt{2 x}\}$$

a) $\mathbb{R}^{+}$b) onto

Algebra

Chapter 4

RELATIONS AND FUNCTIONS

Section 1

Relations and Functions

An Introduction to Geometry

Functions

Linear Functions

Polynomials

Missouri State University

McMaster University

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were first asked to find the domain of the function. Why equal to the square root of two X in order for white of you to find that it must be true that two exes more than equal to zero. So the demand of dysfunction is all non negative. Real numbers now ask to find dysfunction is onto. Given that set A is equal to set B, dysfunction is onto, if suddenly is equal to the range from Part A. We found at the set A, which is equal to the domain, is the set of all non negative real numbers and were given that this is equal to set B. No, it's fine. The range of dysfunction, the square root of any real number is either zero or positive. So the range of dysfunction is why it's more than equal to zero. This is equal to set me. And so this function is on two

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