in-12-23-each-set-is-a-function-from-set-a-to-set-b-a-what-is-the-largest-subset-of-the-real-numbe-9

Question

In $12-23,$ each set is a function from set $A$ to set $B .$ a. What is the largest subset of the real numbers that can be set $A$ , the domain of the given function? b. If set $A=\operatorname{set} B,$ is the function onto? Justify your answer. 
$$
\left\{(x, y) : y=\frac{1}{\sqrt{x+1}}\right\}
$$

Emma Chickles · Accepted Answer

in this problem where first has to find the dominion of dysfunction for why, to me to find then the value Under this great root sign experts one has been more than their equal to zero. Isolating for X. This gives us that X has to be more than or equal to negative one. Another requirement for white we defined is a The denominator has to not be equal to zero. This will happen on Lee when X is equal to negative one. So this fully defines our domain as X has been more than but not equal to negative one. Now asked to find a dysfunction is onto. Given that set A, which is the domain is equal to set B. The function is onto if the range is equal to set B. So let&#x27;s find the range of dysfunction. The denominator of this function is always going to be positive. Since the square root of any real number is positive, this is not equal to set B, which is that why has before the next one. And so this function is not on two

Emma Chickles · Answer

were first asked to find the domain of the function. Why equal to the square root of two X in order for white of you to find that it must be true that two exes more than equal to zero. So the demand of dysfunction is all non negative. Real numbers now ask to find dysfunction is onto. Given that set A is equal to set B, dysfunction is onto, if suddenly is equal to the range from Part A. We found at the set A, which is equal to the domain, is the set of all non negative real numbers and were given that this is equal to set B. No, it&#x27;s fine. The range of dysfunction, the square root of any real number is either zero or positive. So the range of dysfunction is why it&#x27;s more than equal to zero. This is equal to set me. And so this function is on two

Emma Chickles · Answer

this question first asked us to find the domain of this function in order for white tree to find than X minus one cannot be equal to zero where X minus one is the denominator of this function. So the domain of dysfunction is a set of all real numbers, not including one. Now we&#x27;re asked to find a dysfunction is onto. Given that set A, which is the main is equal to set B. The function is onto if set b is equal to the range. So let&#x27;s find the range of this function as X goes to infinity Positive infinity. Why ghost is here? Why goes to one? Mike Weiss is as X goes to negative infinity. Why also goes to one but doesn&#x27;t reach it. So the range of dysfunction is that why cannot be equal to one since I was a nascent Oh, at y equals one. This is equal to set a the domain and is equal Sepi. Since we&#x27;re given that said, a is equal to set B So this function is onto Since range, the range is equal to set B

Emma Chickles · Answer

this problem First assets to find the domain of the function. Why equal to one over X in order for why to be defined than X cannot be goal to zero. So this Khuzestan Amane of all real numbers except zero Now we&#x27;re asked to find it&#x27;s a function is onto given upset. A wishes remain is equal to set B. The function is onto a set. B is equal to the range. So let&#x27;s determine the range of this function. As X goes to infinity, Why goes to zero but doesn&#x27;t reach it, so why can never be equal to zero? As we can see, the range is equal to set A which is equal to set B. Therefore, this function is on two.

Emma Chickles · Answer

and this question where first asked to find the domain of the function y equals X squared and this function X could be equal to any real number. So the domain is a set of all real numbers. Now we&#x27;re asked to find if the function is onto If set A is equal to Set B, which also is equal to the domain or the sight of all real numbers the function is onto. If set B is equal to the range. So let&#x27;s determine what the range of this function is. X squared is always positive or zero. So the range of this function is why is more than your equal to zero? This is not equal to the set B, and therefore this function is not on two.

Emma Chickles · Answer

and this problem refers as to find the domain of the function. Why equal to negative 1 83 in this case, that X can be equals any real number. So the domain is a set of all real numbers. Now ask to find of this function is onto. Given that set, A is equal to set B from party, we&#x27;ve determined that set A is equal to all real numbers. So the cell so must be equal to set B. The function is onto if the range sequel to set B. So let&#x27;s determine the range. In this case, why can all be equal toe one value negative 1 83? As you can see, the range is not equal to set B, and therefore this function is not on two.

Problem

In $12-23,$ each set is a function from set $A$ t…

Problem 20 Medium Difficulty

In $12-23,$ each set is a function from set $A$ to set $B .$ a. What is the largest subset of the real numbers that can be set $A$ , the domain of the given function? b. If set $A=\operatorname{set} B,$ is the function onto? Justify your answer.
$$
\left\{(x, y) : y=\frac{1}{\sqrt{x+1}}\right\}
$$

Answer

a) $>-1$
b) not onto

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a) $>-1$b) not onto

Algebra 2 and Trigonometry

Catherine R.

Anna Marie V.

Heather Z.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

Ann Xavier GantertAlgebra 2 and Trigonometry

Catherine R.

Anna Marie V.

Heather Z.

Michael J.

a) $>-1$
b) not onto

Ann Xavier Gantert

Algebra 2 and Trigonometry