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In $12-23,$ each set is a function from set $A$ to set $B .$ a. What is the largest subset of the real numbers that can be set $A$ , the domain of the given function? b. If set $A=\operatorname{set} B,$ is the function onto? Justify your answer. $$\left\{(x, y) : y=\frac{1}{\sqrt{x+1}}\right\}$$

a) $>-1$b) not onto

Algebra

Chapter 4

RELATIONS AND FUNCTIONS

Section 1

Relations and Functions

An Introduction to Geometry

Functions

Linear Functions

Polynomials

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in this problem where first has to find the dominion of dysfunction for why, to me to find then the value Under this great root sign experts one has been more than their equal to zero. Isolating for X. This gives us that X has to be more than or equal to negative one. Another requirement for white we defined is a The denominator has to not be equal to zero. This will happen on Lee when X is equal to negative one. So this fully defines our domain as X has been more than but not equal to negative one. Now asked to find a dysfunction is onto. Given that set A, which is the domain is equal to set B. The function is onto if the range is equal to set B. So let's find the range of dysfunction. The denominator of this function is always going to be positive. Since the square root of any real number is positive, this is not equal to set B, which is that why has before the next one. And so this function is not on two

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