in-13-22-solve-each-equation-or-inequality-each-solution-is-an-integer-2-x3-x15

Question

In $13-22,$ solve each equation or inequality. Each solution is an integer. 
$$
2 x+3 < x+15
$$

Aditya Sood · Accepted Answer

Hello. Everybody solve each equation or inequality. Each solution is an integer. So, uh, this isn&#x27;t inequality right over here, and it is to X for three is less than extra 15. So our first step is going to be to isolate the variables, to bring them all to the left hand side, are to a side in this case, is going to the left hand side and to eventually get it by itself on that side. So we want to subtract by ex both as the ex. So we get expert three is less than 15. Now, to get X myself on the left hand side, you want subtract both sides by three. So you get X is less than 12. Since this is inequality, the solutions to this inequality are all integers less than 12. And so a way of expressing this would be right here. This is the domain of X, And so ah, fancy What is essentially just a fancy way of writing that, uh, all values from negative infinity to 12 are solutions to this inequality. And one thing to notice is this right? Here it is a apprentices, which means that 12 itself is not included. So, uh, it&#x27;s from negative Infinity to 12 not including 12

Joshua Utley · Answer

All right, We&#x27;re asked to solve this equation. This inequality for ex Excuse me. And so what I&#x27;m going to do and it looks like, accidentally I made a slight type of when writing this down. This should just be minus three here. You should not be an X there. Excuse me. All right. So the way I choose to do this is I would add two x thio each side. I was gonna leave you in minus three, greater than or equal to 12 plus three acts, and then he&#x27;s attract 12 over. So you&#x27;re gonna have minus three and minus 12 is minus 15 greater than or equal to three X, and then you&#x27;ll have X less than argue books it right here. And my five. Yeah.

Aditya Sood · Answer

solve each in quality or equation. Each solution isn&#x27;t integer seven X plus five is equal to four X plus 23. We wantto isolate the variable X, and our first step in doing so will be to subtract five from both sides. So we get seven. X is equal to four X plus 18. Now to get all the exes on the left hand side we want is a crack for X from both sides. So we get three exes, you go to 18. Our last step is to get rid of the coefficient of X, and we can do so by dividing it by three by dividing by three, we get three X over three and in this case that threes We&#x27;ll just cancel out and we get is equal to 18 over three. So we get access equal to 18 over three or X is equal to six

Aditya Sood · Answer

soft each equation or inequality. Each solution is an integer. So this is an equation. And like any other equation when solving for a we want to isolate the variable on one side. So our first step is going to be to subtract three a from both sides so we can bring all the age to the left hand side. So when we do this, we get, uh, we get seven minus five. A is equal to 32. Our next step is going to be subtract seven from both sides. So we get negative. Five way is equal to 32 minutes seven, which is 25. Lastly, we wanted to fight divided by negative five to get rid of the coefficient of a and so we get a is equal to negative five.

Yuanchun Ye · Answer

um, for the equation. 13 miners acts you close to 15. We would first subject each far each part of the equation by 13. So this would be 13 miners Max Miner, 13 and the right heart with the 15 miners. 30. So we know 13. Mind searching you close to zero. So it would be miners X in the left part. It would be too underground part and we would divide this equation off both sides by miners one. So that would be miners axe over minor swat and the right part would be to over miners want and it closed two x I&#x27;ve left and it closed Two minors, two on the right. So the solution is acts close to minors to

Joshua Utley · Answer

okay were as to solve the following inequality. For why and so what I&#x27;m gonna start by doing is adding a one toe both sides of my inequality. Inequality signs have certain properties that are different from equal signs. But with addition, it&#x27;s the same rule you just add and subtract on both sides. And so you&#x27;d be left with five. Why is greater than or equal to two? Why plus six? And from here I would subtract two y from both sides, and I would be less with three y is greater than or equal to six. And then I can divide by three on both sides and leave me with why is greater than or equal to two and you&#x27;re done.

Problem

In $13-22,$ solve each equation or inequality. Ea…

Problem 17 Medium Difficulty

In $13-22,$ solve each equation or inequality. Each solution is an integer.
$$
2 x+3 < x+15
$$

Answer

$x \in(-\infty, 12)$

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Ann Xavier Gantert

Algebra 2 and Trigonometry

Anna Marie V.

Alayna H.

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Maria G.

Absolute Value - Example 1

Absolute Value - Example 2

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$x \in(-\infty, 12)$

Algebra 2 and Trigonometry

Anna Marie V.

Alayna H.

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Maria G.

Absolute Value - Example 1

Absolute Value - Example 2

Ann Xavier GantertAlgebra 2 and Trigonometry

Anna Marie V.

Alayna H.

Kayleah T.

Maria G.

Ann Xavier Gantert

Algebra 2 and Trigonometry