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In $13-22,$ solve each equation or inequality. Each solution is an integer. $$(b-1)-(3 b-4)=b$$

$b=1$

Algebra

Chapter 1

THE INTEGERS

Section 3

Adding Polynomials

The Integers

Equations and Inequalities

Polynomials

Oregon State University

Harvey Mudd College

Baylor University

University of Michigan - Ann Arbor

Lectures

01:32

In mathematics, the absolu…

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01:16

In $13-22,$ solve each equ…

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01:23

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In $3-17,$ solve each equa…

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Hello, everybody. Today we're going to be solving this equation and each solution as an integer. So our equation is B minus one minus three. Minus four is equal to be. So our first step is going to be to distribute out the negative sign so that this equation is equal to B minus one minus three B plus four is equal to be, uh, Now we just want to combine like terms on the left hand side. So we get, uh, be an A B minus. Tree B is all right. We'll be ministry be gives us negative to be and then negative one plus for gives us three. So we get negative to be plus three is equal to me. Ah, Now we want to bring it to be over to the right answer so that we could get all the variable terms on to one side. So we get three b is equal to three, divide both sides by three to get B is equal to one, and that is our solution.

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