in-18-23-write-and-solve-an-equation-or-an-inequality-to-solve-the-problem-in-an-algebra-class-3-stu

Question

In $18-23,$ write and solve an equation or an inequality to solve the problem.
In an algebra class, 3 students are working on a special project and the remaining students are working in groups of five. If there are 18 students in class, how many groups of five are there?

Aditya Sood · Accepted Answer

right and solve in equation to solve the problem. In algebra class three students are working on a special project in the remaining Eastern&#x27;s working in groups of five. If they&#x27;re 18 students in the class, how many groups of five are there? So we know that Totals 18 and three are working on their own project, so we can do it. 18 minus three is equal to five. X and X is the total number of groups that are, and the reason we multiply that by five is because there are five students in each group, so we can further evaluate this. To get 15 is equal to five. X X is equal to three, so we know that there are three groups of five.

Ankit Gupta · Answer

five times off X plus three moored minus two articles to 18. Adding To get fired times off Markoff Express trees because to 20 but X plus three is equals to four. This absolute value function will have focused when X plus three articles +24 or been explicit because to minus four, subtracting three from both sides with it, except it goes to one or accept a close to minus seven. So the solution, said for the given question, is minus seven common one.

Kimberly Konzack · Answer

Okay, So in this problem, which is number four, we have 18 X minus. Phi is less than or equal to three parentheses. Six X minus two. The first thing we should do is distribute using the distributor property to get the number is out of the parentheses. So 18 X minus sechs. At this point, let&#x27;s say you were to try to move the exes over to the other side. You get negative. 18 X. Or maybe he did it the other way. In either case, you get negative. Five is less than or equal to negative six. Okay, so you&#x27;re left with and in equality. Okay, so is negative. Five less than or equal to negative sex. That is false. Therefore, there is no solution. So no solution. This is the and D set or the no set. So no solution. Not sure for any meal.

Yuanchun Ye · Answer

unless first defying X. That&#x27;s the amount off. As a DEA. Andi, we defined why, as the amount off the opinion. So we will get equation 19 X plus five. Why is less than 49 and we would get five. Why is dust and 49 miners on 19 X and we know acts is larger or equal to zero. So miners 90 x iss either equals to zero or positive in them or inactive number. So we know this is not active, and, um, we won&#x27;t you get the maximum value off. Why? So we need the right part to be as large as possible. So we would get the the part, uh, miners 19 x to be zero. So, um, when it close to zero, the right part would be the largest. So why would be the largest? So we was then self the equation that hiss five. Why, oh, less less than 49. And why is the last 49 over five? So, um, because why is that integer? So we&#x27;ve got Cem largest in future. That is, Let the last thing for 49 over five is NY. So the answer for the problem is no

Julie Silva · Answer

we&#x27;re being asked to solve the given equation for X. Well, the first we want to do is get rid of our fraction. I remember Fraction means division. So the opposite of dividing by two is the multiply by two. So we&#x27;re going to multiply both sides of our equation by two. Now, on the left hand side, the twos, they&#x27;re going to cancel each other row. So we&#x27;re just left with three X and on the right hand side, we just multiply. Well, negative. 18 times two is negative. 36 now to solve for X, we just need to divide both sides by three because the threes on the left hand side will cancel. And on the right hand side, we have negative 36 divided by three, which is negative. 12. And now we&#x27;ve solved our equation for acts and our solution is negative. 12

Heather Zimmers · Answer

If we were solving this inequality, we would want to get em by itself. So we would need to add 18 to both sides. That&#x27;s the step we would do. If we actually do it, we would have. 23 is greater than M, and that&#x27;s the same thing as M is less than 23.

Problem

In $18-23,$ write and solve an equation or an ine…

Problem 19 Easy Difficulty

In $18-23,$ write and solve an equation or an inequality to solve the problem.
In an algebra class, 3 students are working on a special project and the remaining students are working in groups of five. If there are 18 students in class, how many groups of five are there?

Answer

3 groups of 5

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3 groups of 5

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Catherine R.

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Absolute Value - Example 1

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Ann Xavier GantertAlgebra 2 and Trigonometry

Catherine R.

Caleb E.

Maria G.

Kristen K.

Ann Xavier Gantert

Algebra 2 and Trigonometry