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Hello.
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So in this problem, we're speaking about a hurricane that happened in 2005.
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And due to this, some students flee from houston to texas, which is 199 meters north from houston.
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The description of the trip that the students traveled the first quarter of their trip at 3 meters per second, then the next quarter they travel at 4 .5 meters per second, and for the rest of the trip, which is half of time, they were traveling at 6 meters per second.
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The question is to determine how long did it take for those students to reach their destination at texas? so in order to do this, let's first determine the distance from houston to texas but in meters instead of mines.
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So we know that one mile is equal to 1 ,609 meters approximately.
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So the distance in that case is 199 multiplied by 1009, which is approximately 3009.
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120 times 10 to the power of 3 meters.
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So that's the distance measured in meters.
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In order to get the time, we need to get the average velocity.
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And if we divide the distance by the average velocity, now we have the time that it takes for the students to get there.
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So to get the average velocity, the average, we need here to multiply 3.
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Times one quarter plus 4 .5 multiplied by one quarter plus 6 multiplied by one half.
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And we will get the average velocity which is 4 .875.
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Then we can directly calculate the time by dividing distance over velocity or the average velocity.
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So here we have 320.
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Multiplied by 10 to the power of 3 divided by 4 .875.
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And the answer is around 65 ,0694.
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Approximately, this is in seconds.
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Dividing this by 3 ,600, we get the answer which is around 18 .2 hours.
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And that's the time that it takes the students to reach their destination.
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In the second part, we're asked to sketch a graph of the position versus time for this entire trip...