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In $2012,$ Felix Baumgartner jumped from a balloon roughly $24 \mathrm{mi}$ above Earth, breaking the record for the highest skydive. He reached speeds of more than 700 miles per hour and became the first skydiver to exceed the speed of sound during free fall. The helium-filled plastic balloon used to carry Baumgartner to the edge of space was designed to expand to $8.5 \times 10^{8} \mathrm{L}$ in order to accommodate the low pressures at the altitude required to break the record. (a) Calculate the mass of helium in the balloon from the conditions fall. The helium-filled plastic balloon used to carry Baumgartner to the edge of space was designed to expand to $8.5 \times 10^{8} \mathrm{L}$ in order to accommodate the low pressures at the altitude required to break the record. (a) Calculate the mass of helium in the balloon from the conditions

(a) $7.2 \mathrm{kg}$(b) $4.4 \times 10^{4} \mathrm{L}$

Chemistry 101

Chapter 5

Gases

University of Central Florida

Rice University

University of Maryland - University College

Lectures

05:03

In physics, a gas is one of the three major states of matter (the others being liquid and solid). A gas is a fluid that does not support tensile stress, meaning that it is compressible. The word gas is a neologism first used by the early 17th-century Flemish chemist J.B. van Helmont, based on the Greek word ("chaos"), the simplest of all the elemental forms of matter.

04:46

In physics, thermodynamics is the science of energy and its transformations. The three laws of thermodynamics state that energy can be exchanged between physical systems as heat and work; that the total energy of a system can be calculated by adding up all forms of energy in the system; that energy spontaneously flows from being localized to becoming dispersed, spread out, or uniform; and that the entropy of an isolated system not in equilibrium will tend to increase over time, approaching a maximum value at equilibrium.

01:53

On October 14, 2012, Felix…

00:28

Felix Baumgartner, wearing…

09:20

The fastest recorded skydi…

01:06

On October 14, 2012, dared…

00:41

The world record for the h…

05:29

Although balloons have bee…

05:28

Scientific balloons operat…

01:22

The greatest height report…

02:03

02:11

Free fall On October $14,2…

07:40

An 80.0 -kg skydiver jumps…

02:02

An inflated rubber balloon…

We have the volume of the volume of boulogne is 8.5 multiply, 10 raised to the power 8 liter temperature temperature of minus 67.8 degrees centigrade in pressure and pressure pressure of 0.027 millimeter of mercury. We need to find we need to find, but a the mass of the mass of helium and in part b, the volume when pressure is equal to 1.0 standard atmospheric pressure and t is equal to 23 degrees celsius. Calculation for a use, ideal, ideal gas equation equation to find the number of on the number of moles number of moles of helium at e, then then, then multiply multiply then multiply it with it, with the molar mass of the molar mass of helium to obtain the Mass obtain the mass mass is equal to in molar. Mass is equal to p v out of r t into m. Mass is equal to is equal to. We have 0.027 millimeter of mercury into 1 standard atmospheric pressure divided by 760 millimeters of mercury into 8.5 multiply. 10 raised to the power 8 liter into 4.003 gram per mole into 1 kg divided by 1000 gram, so 0.0821 liter at m per mole per kelvin into minus 67.7 plus 273 kelvin equal to mass is equal to 7.2 kelgpart b to find the volume to find The volume when the pressure and temperature, the pressure in temperature is change, pressure and temperature pressure is changed. We can use combined, can use combined geslonthe combined gisla is p 1 v 1 divided by t 1 is equal to p 2 v 2 divided by t 2 point so putting values and the above combined gesler. We have values here: 0.027 milimeters of mercury into 1 standard atmospheric pressure divided by 760 molimeter of mercury into 8.5 multiplied 10 raised to the power 8 later divided by minus 67.8 plus 273 kelvin is equal to. We have 1.0 standard atmospheric pressure into v, 2 divided by 23 plus 273 kelvin now solve for v, 2 v 2 v 2 is equal to we have v. 2 is equal to 88.5. Multiply 10 raised to the power 8 later into 0.027 millimeter eh g into 180 m standard atmospheric pressure divided by 760 millimeters of mercury millimeter of mercury into we have 23 plus 273 kelvin divided by minus 67.8 plus 273 kelvin divided by 1.0 standard atmospheric pressure. V. 2 is equal to 4.4 multiply 10 raised to the power 4 later.

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