in-26-37-find-each-product-12-2-i12-2-i

Question

In $26-37,$ find each product.
$$
(-12-2 i)(12-2 i)
$$

Heather Zimmers · Accepted Answer

to multiply complex numbers. We use the same method we would use if we were multiplying by no meals, which is the foil method. So we multiply the first and we get negative. 1 44 We multiply the outsides and we get 24 I we multiply the insides and we get negative 24 i and we multiply the last someone give for I squared. Notice that 24 I and negative 24 I add to zero. And also remember that I squared is negative one. So we have negative 1 44 plus four times negative one. We can write that as negative 1 44 minus four and that would be negative 1 48

Heather Zimmers · Answer

to multiply complex numbers. We use the same method we would use if we were multiplying by no meals. And that would be the foil method. So we multiply the first and we get negative, too. Welcome by the outsides, and we get negative. Four. I multiply the insides and we get negative one I and multiply the last time we get negative to I squared. Let&#x27;s combine the inside and outside terms so we have negative two minus five I and then remember that I squared is negative one. So we have minus two times negative one. So we&#x27;ll simplify that. We have negative two minus five I plus two and we can add the negative to in the plus two and they just give us zero. So in standard form we have zero minus five I

Heather Zimmers · Answer

to multiply complex numbers. We use the same technique we would use to multiply by no meals, and that would be the foil method. So we multiply the first and we get 12. We multiplied the outside&#x27;s when we get negative. Eight. I we multiply the insides and we get negative. 15 I and we multiply the last and we get plus 10. I squared. Now let&#x27;s combine like terms. Negative eight I and negative 15 I and we have 12 minus 23 I and remember that I squared is negative one. So we have plus 10 times negative one. So if we simplify that, we have 12 minus 23 I minus 10. And let&#x27;s go ahead and add those like terms together, and our final answer will be to minus 23 I

Jeremy Strong · Answer

for this problem. We were asked to multiple of the complex number two monastery, Uh, by itself or two squared. So were you riding to monastery? A squared as to Mona&#x27;s three. Ah, Tom&#x27;s two minus three I now we need to foil as usual. So two times two is going to give us four and then two times negative three. I was going to give us mon ist six I and then our inner terms negative three times two is going to give us another mon ist six, huh? And then our last terms. Now you&#x27;re three on native three are going to give us a plus non. I squared, all right. And now we may start to begin to combine our like terms. So we have four and then we have minus six on minus six I, which is minus 12 huh? When we have plus non squared but squared is the square root of negative one squared, which is negative one. So we actually have four. Mona&#x27;s non and then we have modest 12 I and this will give us our final answer, which is negative. Five mon ist 12. I

Jeremy Strong · Answer

in this problem. We&#x27;re asked most by the complex number 1/5 Modest. 1/10 of the complex number four plus two. Uh, so we will perform multiplication as usual, using the foil method. So to begin, we have 1/5 Tom&#x27;s four, which is going to give us four. It&#x27;s okay. And then our outer terms are we have 1/5 and we have to Ah, multiplying this together is going to get us to fifths, huh? And then our inner terms, we have modest 1/10 I and we have four. Multiplying them is going to give us modest four chance high in our last terms. Won&#x27;t negative 1/10 and positive to our We&#x27;re gonna give us a modernist to over 10 uh, squared. Now I squared is the same thing is negative one because it is the square root of negative one squared. So we have modest to chance times negative one. So, actually, what we can do here is we can forget. The negative one is here and make the 2/10 positive. Now we need to combine our real parts and our imaginary parts. So we have 4/5 and we have plus two chance. So 4/5 is the same thing is a chance. And then we have plus to chance for a real component. And then we have 2/5 Monas for Fitze has shown here. So what we could do is we could rewrite to Fitz a cz four over 10. Uh and then we have Monness 40 Virgin, huh? So for our real component, we have 8/10 plus two chance, which is Jan over 10. And then for our imaginary component, we have four chance. Ah, modest fortune saw, which is zero I and 10 over 10. Plus Cyril, I may be rewritten as simply one, which is final answer.

Jeremy Strong · Answer

for this problem were asked by the complex number one plus fava by the complex number one plus two. So to do this we may use the foil method. So we 1st 1 won&#x27;t spot one times one to get one and then we multiply the outer terms the two I and the one which will give us a plus two. Uh And then we will multiply the inner terms five and one to give us a plus five I And then we were multiple. The last terms which will be the five and the two I to give us plus 10 squared. Now if we attempt to add correspondent components, we have one and then we have a two and a father which combining with seven and then we have plus 10 times square. Now I squared is the square root of negative one squared, which is actually negative one. And this works out to be one mon ist tim plus seven I, which is equal to negative non plus seminar and negative non plus seven. Ah, is the final answer

Problem

In $26-37,$ find each product. $$ (5-3 i)(5+3 i…

Problem 33 Medium Difficulty

In $26-37,$ find each product.
$$
(-12-2 i)(12-2 i)
$$

Answer

$-148$

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Ann Xavier Gantert

Algebra 2 and Trigonometry

Grace H.

Anna Marie V.

Caleb E.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

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$-148$

Algebra 2 and Trigonometry

Grace H.

Anna Marie V.

Caleb E.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

Ann Xavier GantertAlgebra 2 and Trigonometry

Grace H.

Anna Marie V.

Caleb E.

Michael J.

Ann Xavier Gantert

Algebra 2 and Trigonometry