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In $3-14,$ write the solution set of each equation.$$|8+2 b|-3=9$$

$b=-10,2$

Algebra

Chapter 1

THE INTEGERS

Section 4

Solving Absolute Value Equations and Inequalities

The Integers

Equations and Inequalities

Polynomials

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Campbell University

Harvey Mudd College

Idaho State University

Lectures

01:32

In mathematics, the absolu…

01:11

01:22

In $3-14,$ write the solut…

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01:26

00:09

Find the solution set for …

00:43

Solve each equation.$$…

01:04

Solve each equation. Check…

01:14

01:02

03:36

Solve each equation. $…

00:23

Solve each absolute value …

right. The solution set of each equation absolute value of eight plus two b my history is it on tonight? So our first step is going to be to add three to both sides. So we get absolute value of eight plus to be easy for 12. And that's important to see that this is actually in the same form as absolute value off A is going to be. And when you have form like this, there's, ah, we want to break you down into two separate equations to get are two separate solutions. So the absolute value of a is going to be can be broken down into a zero to be and easy with negative B and you saw of each of these equations separately and you get your two solutions. So we're just going to apply that same concept right over here for a problem. And so we're going to break eight absolute value of eight plus two B is equal to 12. Uh, we're gonna break that under two chunks. So on the left side, we got eight plus to be easy with 12 and on the right side, we have a place to be is it wouldn't negative 12. And so now we're just going to evaluate this as normal algebraic equation. So we want to subtract under on the left equation. We're going to subtract eight from both sides, so we're left with two B is equal to four and divide both sides by two until we get our one solution of bees that were too. Now, on the right equation, we're gonna do a similar thing. We're going to subtract it from both sides to get too busy with the negative 20. Divide both sides by two, and we get busy with the negative 10. And now we know that a solution for this equation is B is equal to and be easy with the negative time.

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