in-3-17-find-each-sum-or-difference-of-the-complex-numbers-in-ab-i-form-2-8-i-28-i

Question

In $3-17,$ find each sum or difference of the complex numbers in $a+b i$ form.
$$
(2-8 i)-(2+8 i)
$$

Heather Zimmers · Accepted Answer

to find the difference of these complex numbers. I&#x27;m going to start by distributing the negative. So we have two minus eight. I minus two minus eight. I Now we can combine the rial parts to minus two and that gives us zero, and we can combine the imaginary parts. Negative eight i and negative eight I and that gives us negative 16 I. So writing it in a plus B I form is zero minus 16. I

Jeremy Strong · Answer

in this problem, we&#x27;re asked to combine the complex number four plus 12. Ah, to the complex number negative form. Honest to, uh so what we need to do is we need to combine our lock terms, meaning we first need to combine our real terms, which would be the four and the negative four. And then we&#x27;re going to need to combine our 12 in our negative to ER which is our imaginary component. So four less negative for is going to give us zero and then 12 I plus negative to It&#x27;s going to give us plus 10. All right, since our real part is works out to be zero, the final answer can also be written as simply 10.

Heather Zimmers · Answer

to find the some of these complex numbers. We want to add the rial parts together and add the imaginary parts together. So with a little bit of fraction work to do 3/7 plus 1/6 we&#x27;re going to get a common denominator of 42. So we multiply the first fraction by 6/6, and we get 18/42. Now we multiply the second fraction by 7/7, we get 7/42 so that one is 25/42. So that will be the real part of our answer. And then, for the imaginary part of her answer, we need to take 1/3 minus 7/8. Let&#x27;s get a common denominator of 24 and so will multiply the first fraction by 8/8, and we get 8 24th I multiplied the second fraction by 3/3, and we get 21 24th and eight minus 21 is negative. 13 some negative, 13 24th. So that means that the imaginary part of our answer is negative. 13 24th I. So we put it all together, and there&#x27;s our standard form of our answer.

Heather Zimmers · Answer

to find the some of these complex numbers. What we want to do is add the rial parts five plus four and that would be nine. And then we add the imaginary parts negative six i and two I and that would be minus four I. So we get nine minus for I.

Heather Zimmers · Answer

to find the some of the complex numbers. We can add the rial parts six plus one and we get seven and then we can add the imaginary parts seven I plus two I and we get nine I. So our answer is seven plus nine. I

Jeremy Strong · Answer

for this problem. We&#x27;re asked to combined the complex number 1/2 plus 1/2 I to the complex number 1/4. Mona&#x27;s 3/4 now working with fractions might be a little bit more confusing to begin with, but it could be made very simple to begin. Ah, one method of approaching this problem would be to find a common denominator. So that addition will be made much easier in this complex number. We see that the denominator is four. And in this when we have a two. So what we may do is rewrite the first complex number. So the denominator is four. So we might actually have 2/4 plus 2/4 and then plus 1/4 monness 3/4. So now that all of our opponents are in terms of division before well, you may now just add our correspondent components as usual. So we have a 2/4 plus 1/4 so that works out to be 3/4 and then we have plus 2/4 monness 3/4. What? Just going to give us negative 1/4 and this is our final answer.

Problem

In $3-17,$ find each sum or difference of the com…

Problem 7 Easy Difficulty

In $3-17,$ find each sum or difference of the complex numbers in $a+b i$ form.
$$
(2-8 i)-(2+8 i)
$$

Answer

$0-16 i$

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Ann Xavier Gantert

Algebra 2 and Trigonometry

Grace H.

Anna Marie V.

Kristen K.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

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$0-16 i$

Algebra 2 and Trigonometry

Grace H.

Anna Marie V.

Kristen K.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

Ann Xavier GantertAlgebra 2 and Trigonometry

Grace H.

Anna Marie V.

Kristen K.

Michael J.

Ann Xavier Gantert

Algebra 2 and Trigonometry