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In $3-17,$ find each sum or difference of the complex numbers in $a+b i$ form.$$\left(\frac{1}{2}+\frac{1}{2} i\right)+\left(\frac{1}{4}-\frac{3}{4} i\right)$$

$\frac{3}{4}-\frac{1}{4} i$

Algebra

Chapter 5

QUADRATIC FUNCTIONS AND COMPLEX NUMBERS

Section 5

Operations with Complex Numbers

Equations and Inequalities

Quadratic Functions

Complex Numbers

Polynomials

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for this problem. We're asked to combined the complex number 1/2 plus 1/2 I to the complex number 1/4. Mona's 3/4 now working with fractions might be a little bit more confusing to begin with, but it could be made very simple to begin. Ah, one method of approaching this problem would be to find a common denominator. So that addition will be made much easier in this complex number. We see that the denominator is four. And in this when we have a two. So what we may do is rewrite the first complex number. So the denominator is four. So we might actually have 2/4 plus 2/4 and then plus 1/4 monness 3/4. So now that all of our opponents are in terms of division before well, you may now just add our correspondent components as usual. So we have a 2/4 plus 1/4 so that works out to be 3/4 and then we have plus 2/4 monness 3/4. What? Just going to give us negative 1/4 and this is our final answer.

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