in-3-17-solve-each-equation-or-inequality-each-solution-is-an-integer-13-x15

Question

In $3-17,$ solve each equation or inequality. Each solution is an integer.
$$
13-x=15
$$

Yuanchun Ye · Accepted Answer

um, for the equation. 13 miners acts you close to 15. We would first subject each far each part of the equation by 13. So this would be 13 miners Max Miner, 13 and the right heart with the 15 miners. 30. So we know 13. Mind searching you close to zero. So it would be miners X in the left part. It would be too underground part and we would divide this equation off both sides by miners one. So that would be miners axe over minor swat and the right part would be to over miners want and it closed two x I&#x27;ve left and it closed Two minors, two on the right. So the solution is acts close to minors to

Yuanchun Ye · Answer

for these equation way with first at H two and both sides off the equation. So that would be too packs on past three, um, gather the absolute value it crossed through 15 plus eight. So it would be so. This would be 23 and we know on the absolute value of two X plus three equals to 23. So true express three close to either 23 or miners 23. And, well, we would so close off the equations for the equation. Truax miners three. You close to, uh, across to a 23? Oh, Um, yeah, it crossed through 23. We would, um, subject three for the most part, So that would be two. X equals to 23 minor. Three. And this would be true. True ex because to 20. So we know X equals through 10. And for the second equation, we would do to acts minor. Three equals true miners 23. So we would subtract three for both parts. That would be two acts closed to minors. 23 minor. Three. So true acts it closed. Two minors 26 and we would conclude X equals two minors. 13. So There are two solutions. The first one&#x27;s acts equals to 10 and Third World, and the 2nd 1 is acts it close to my nurse, 30.

Aditya Sood · Answer

so each inequality. This each solution is an integer, and we&#x27;re solving for a in the equation. 78 plus three is greater than 17. So we want to treat this like any other equation. And so we will want to isolate a variable. And so our first step is going to be too surprised. Negative three from both sides. So we get seven. A is greater than 14. Then to further isolate a we want to get hurt if it&#x27;s cool, fishing off seven. So we divide both sides by seven and we&#x27;re left with a is greater than two.

Aditya Sood · Answer

okay, Solve each equation or inequality. Each solution is an integer. The expression below is five. X plus four is equal to 39 and we&#x27;re solving for X. So our first step is going to be to isolate the X variable. And in order to do so, we must move the plus four over here, over to the right hand side and in due. So we get five X is equal to 35. Our next step will be to further isolate the variable X by dividing both sides by five and showing right here. So we get five. X, divided by five is equal to 35 over five. The fives will cancel out. That&#x27;s five over 50 to 1 and 35 over five is equal to seven. And so what we get down here is X is equal to seven.

Yuanchun Ye · Answer

home for these equation, we would first saps our subtract 18 from both sides. So that is seven acts plus 18 miners 18 and the right heart is 39 liners 18 and we would compute this. This is close to zero. So this question would be seven acts you close to for this part it close to on 21. So this question so the question would be transferred into seven x equals to 21 and then we would subtract seven. Oh, we would device seven from both sides. That is, someone acts divided by seven equals true, 21 over seven. So this would be acts in close to three. So this is the solution for the equation.

Yuanchun Ye · Answer

So first we would concert on, uh, left part off this inequality that his hero is nest. So Axe Minor three. And we would at three to both sides at his Nero plus three ness than X miners. Three, class three. So the last part would be three. And the right part would be ext. So the left part of this equation would be X. Um, it would be a three less than X unless computer right part. It would be ex miner three. Last time, four. And we would add three to both sides. That is, ext. Minor. Three, uh, class three lesson for the last three. So the last part would be X, and the right part will be seven. So then we would come by, um, the first target through the second part that his ex three is less than an axe. Lesson seven. This would bids a solution

Problem

In $3-17,$ solve each equation or inequality. Eac…

Problem 8 Easy Difficulty

In $3-17,$ solve each equation or inequality. Each solution is an integer.
$$
13-x=15
$$

Answer

$x=-2$

Related Courses

Algebra 2 and Trigonometry

Related Topics

Discussion

Top Algebra Educators

Anna Marie V.

Alayna H.

Maria G.

Michael J.

Algebra Courses

Absolute Value - Example 1

Absolute Value - Example 2

Recommended Videos

Watch More Solved Questions in Chapter 1

Video Transcript

Ann Xavier Gantert

Algebra 2 and Trigonometry

Anna Marie V.

Alayna H.

Maria G.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

Additional Mathematics Questions

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

$x=-2$

Algebra 2 and Trigonometry

Anna Marie V.

Alayna H.

Maria G.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

Ann Xavier GantertAlgebra 2 and Trigonometry

Anna Marie V.

Alayna H.

Maria G.

Michael J.

Additional Mathematics Questions

Ann Xavier Gantert

Algebra 2 and Trigonometry