in-3-29-write-each-quotient-in-simplest-form-variables-in-the-radicand-with-an-even-index-are-non--4

Question

In $3-29$ write each quotient in simplest form. Variables in the radicand with an even index are non-negative. Variables occurring in the denominator of a fraction are non-zero. 
$$
\sqrt{50 a^{3}} \div \sqrt{5 a}
$$

M S · Accepted Answer

So you have scared to 50 times a cubed divided by screw of 58 So the person want to do is write this infraction for so have scary with 50 a cute over skirt of five day so I can write this undo one radical And when we do that, we can cancel maker reduces fraction the numbers. So you beat that attorney to attain and five divided by five meetings more from their councils. So we have soon a cute over a And whenever we have the same based and we&#x27;re subtracting and we&#x27;re dividing So let&#x27;s say we have thanks to the a divide about exited beat and we have the same base. This just means we&#x27;re going to subtract the explanation So we haven&#x27;t understood exploitative or in here. So three months, one day out of the once too. So what happens? Girdwood saying I swear. And if you separate these, you know, screw teams on the spirit of a square and this radical cancel out with that swear So we have a time to spread its aim

Matt Gibson · Answer

simplify a problem that has a radical in the numerator and radical in the denominator. I&#x27;m going to write it as one big radical. So dividing to radicals is the same as having one giant radical about with both inside. Now it&#x27;s easy to see that I can reduce. So five goes into the numerator five goes into the denominator. So I wind up with, um, five years into that seven times five goes into the denominator. Two times I reduced my A cube and divide by the A in the denominator leaves me with a square. Now I can&#x27;t have a radical in the denominator, So I have to rationalize this denominator by multiplying the top and bottom by the spirit of to anything divided by itself is one. So I&#x27;m allowed to multiply this by one in the numerator. I now have a square root of 14 a squared in the novel dinner. In the denominator I have the squared of four, which is just to our goal was to rationalize the denominator squared of a squared is a so I wind up with a times the square root of 14 divided by two

Matt Gibson · Answer

any time I have a binomial divided by a mono meal. I need to divide both terms in the numerator. By the denominator, this attraction has to be the same in both. This would then continue. I can think of this is the square root one giant square root. I don&#x27;t have to write it this way, but that&#x27;s what&#x27;s happening. So the left part simplifies to be this way. Before this would wind up being the square root of one. It&#x27;s where the four is two minus one. My final answer would be.

M S · Answer

we want to express this In the simplest form, some little combine them to have one radical. So how 12 a square over for a So the numbers. I&#x27;m just going to divide them by the greatest common factor in this case it&#x27;s for So it&#x27;s low Divided by four gives us three and four divided before we give us one. So have to square a three a squared over a and you&#x27;ll notice that we have the same base here. So whatever we have the same base, the different exponents. We&#x27;re going to subtract er exponents. So this is spirit three and A to the two minus one. You two minus one just gives us one. So just seems to square, huh? Three A.

M S · Answer

So we have five plus six times greater by all over two square beautified. So the first thing I&#x27;m gonna do is separate these instituted with fractions. So why bother us where to buy plus six rebar ever to swear to God. So from the first fraction pair, since we have this radical in the denominator, we need to know ahead. Rationalize it. That just means we&#x27;re gonna multiply the top and bottom by the denominator. So when the most part of top of bottom by scurry by, so have five right by on top and on the bottom. Two radicals council out, and we live with five and then diesel counsel. And from our second fraction, we noticed that we have scary Bible on top and the bottom. So those also counsels. So we have a plus six here that would simplify this down and whispered by bus

Matt Gibson · Answer

when I have a binomial divided by a mono meal. Two terms in the numerator divided by one term in the denominator. This is the same is dividing both terms in the numerator, by the denominator, it subtraction in the middle. So I need to keep that subtraction. Now. I just divide and reduced the image or parts and the radical parts. So in the first term I can cancel, reduce, and then five goes into 10. This is the same as having the square root of 10 divided by five. It&#x27;s the same thing, so that simplifies to be just the square to to I do the same thing Over here. The three of the nine reduce the five in the 50 reduced debate winds up giving me the square root of so three. The nine divided by three and then square to 50 divided by the square to five, gives me the squared attempt to my final answer.

Problem

In $3-29$ write each quotient in simplest form. V…

Problem 6 Easy Difficulty

In $3-29$ write each quotient in simplest form. Variables in the radicand with an even index are non-negative. Variables occurring in the denominator of a fraction are non-zero.
$$
\sqrt{50 a^{3}} \div \sqrt{5 a}
$$

Answer

$a \sqrt{10}$

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$a \sqrt{10}$

Algebra 2 and Trigonometry

Ann Xavier GantertAlgebra 2 and Trigonometry

Ann Xavier Gantert

Algebra 2 and Trigonometry