in-3-8-for-each-function-a-write-an-expression-for-fx-b-find-f5-ysqrtx-1

Question

In $3-8,$ for each function: a. Write an expression for $f(x) .$ b. Find $f(5)$ 
$y=\sqrt{x-1}$

Cory Kuzinski · Accepted Answer

I first off here on this problem, We&#x27;re gonna write this as a and function notation, so just replace the why with the FM back. So it&#x27;s just f of X is equal to the square root of X minus one. So there&#x27;s our function notation. And then for part B, we&#x27;re gonna find f of five, which would be the square root of five minus one or the square to four by minus one is four and swear to four is to so f of five is too.

Cory Kuzinski · Answer

we&#x27;re seeing going to do is right. They function for effort backs. All right, So it would be just f of axe equals X minus two. And that would be our function. Just replacing the why with the f of X. And then we&#x27;re gonna find F at five. Well, that would be instead of X minus 25 minus two, which is three.

Emma Chickles · Answer

and this problem where first asked to rewrite this function in the new notation were given an order pair where the first moment his ex on the second element is five times the value of X. This is equivalent of saying that the function value paired with X is five X. Now it&#x27;s hard to find the function value when X is equal to five. This will be equals of five times five, which is equal to 25.

Emma Chickles · Answer

and this problem were first asked to be right dysfunction in a new notation in the ritual notation. This reads the image of X for the function f is X squared. This is equivalent to saying the function value paired with X is X squared so we can rewrite this and then you notation saying F of X is equal to X squared now, I asked it asked to find the value of F when X is equal to five, this will be equal to five squared, which is equal to 25.

Emma Chickles · Answer

and this problem, we&#x27;re asked to rewrite dysfunction in new notation. The original notations says that the image of X for the function F is too over X. This is equivalent of saying the function value paired with X is to over X. Now we&#x27;re asked to find the value the function value given that X is equal to five stepping five in for X. This gives us two over five.

Cory Kuzinski · Answer

All right, So we&#x27;re doing a couple things here. A we&#x27;re gonna turn this expression into on expression for f of ax. Okay, so exactly 100% sure how your back book would read this, But I read it, as you know, f where X transforms to the absolute value of the reacts minus seven. So mean, very simply, it&#x27;s just gonna be f of ax equals. Absolutely. It&#x27;s the re minus three X minus seven that there&#x27;s our function. All right. And then in part B, we&#x27;re gonna find the value of F at five, which is gonna be the absolute value of three times five, which I&#x27;ll just go ahead and do that right now, which is 15 minus seven. Absolute value 15 minus seven, or the absolute value of eight, which is eight. So F F five or F of five is eight

Problem

In $3-8,$ for each function: a. Write an expressi…

Problem 7 Easy Difficulty

In $3-8,$ for each function: a. Write an expression for $f(x) .$ b. Find $f(5)$
$y=\sqrt{x-1}$

Answer

(a) $f(x)=\sqrt{x-1}$
(b) $f(5)=2$

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Ann Xavier Gantert

Algebra 2 and Trigonometry

Grace H.

Catherine R.

Heather Z.

Alayna H.

Absolute Value - Example 1

Absolute Value - Example 2

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(a) $f(x)=\sqrt{x-1}$(b) $f(5)=2$

Algebra 2 and Trigonometry

Grace H.

Catherine R.

Heather Z.

Alayna H.

Absolute Value - Example 1

Absolute Value - Example 2

Ann Xavier GantertAlgebra 2 and Trigonometry

Grace H.

Catherine R.

Heather Z.

Alayna H.

(a) $f(x)=\sqrt{x-1}$
(b) $f(5)=2$

Ann Xavier Gantert

Algebra 2 and Trigonometry