00:01
So this is a binomial problem, but it's asking us to express this in sigma notation.
00:07
Basically what it's saying is, if we were to do this with just the binomial distribution, we would have to write out multiple binomial distributions.
00:15
But if we use sigma notation, that allows us to write one expression that we could use to plug into a calculator and let the calculator run the multiple binomial distributions necessary.
00:27
It really doesn't change a whole lot except for r.
00:31
On a basic binomial distribution, r represents the number of successes, and there's only one number of successes.
00:38
In this scenario, we have more than one amount of successes that is okay.
00:45
And so instead of just r, now we have r down here on the bottom of the sigma notation, and we have x up here.
00:52
R will represent the lowest amount of successes that we are okay with, and x would be the highest amount of successes we're okay with, meaning we're going to tell the calculator start here and here.
01:04
In this case, it's asking us the probability of at most three losses in the next 10 games.
01:11
At most three, meaning three is the highest amount of losses that we are willing to accept.
01:18
So three is what we would put on top of the sigma notation.
01:23
We don't want the calculator to go any higher than three because four is not okay for this case, right? but the question then is how few of losses? what's the least amount of losses we can have? well, if three is the most, that means two is acceptable.
01:39
That means one is acceptable.
01:41
That means, yes, even zero is acceptable.
01:45
Zero is as low as we can go because, i mean, this is supposed to be real life, and in real life you can't have a negative number of losses, right? you can either have zero losses or you can have more.
01:56
So zero is the lowest amount of losses that we could possibly have, and three is as high as the problem is willing to let us go...