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In $9-26,$ solve each quadratic equation by completing the square. Express the answer in simplest radical form.$$x^{2}+2 x-5=0$$

$-1+\sqrt{6}$ and $-1-\sqrt{6}$

Algebra

Chapter 5

QUADRATIC FUNCTIONS AND COMPLEX NUMBERS

Section 1

Real Roots of a Quadratic Equation

Equations and Inequalities

Quadratic Functions

Complex Numbers

Polynomials

Campbell University

Oregon State University

Baylor University

Lectures

01:32

In mathematics, the absolu…

01:11

02:34

In $9-26,$ solve each quad…

02:32

04:44

05:08

03:06

01:58

03:39

03:53

01:54

kids. The right theory of the expression expert plus two X minus five is equal to zero and we want to solve for X You seen competing square. And if you look at this two x in the middle right here, you will see that you have. Uh, if you have a square root of that, you would have to use one X plus one ex. So in order to get that two exes, that second term. So let's pretend you use X plus one squared. Great. Because X squared plus one plus one ex again would create that middle term right there. But X plus one squared also would create a plus one at the end. So in order to account for that, let's review right originally given problem, that's your right as X squared plus two x, that's right. The plus one here so you can isolate the X plus one squared. And in order for this to work, you have the right side would have to be equal 26 right, cause you do one minus six and you bring over the six other side. You creating negative five on this left side right here. So my little itself, right? You get X plus one squared is equal to six square both sides so that we can solve for X Big X plus one equals plus or minus root. 62 Solutions Because we're solving for a root frost given square, this is the one right here in case I wasn't clear before, Um, finally X equals plus or minus Route six. Bring over that one minus one, and that is solving for X. It's most simplest form.

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