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In $9-26,$ write each expression as the product of two binomials.$$2 y^{2}+5 y-3$$

$(y+3)(2 y-1)$

Algebra

Chapter 1

THE INTEGERS

Section 6

Factoring Polynomials

The Integers

Equations and Inequalities

Polynomials

Oregon State University

Harvey Mudd College

Baylor University

Lectures

01:32

In mathematics, the absolu…

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01:39

In $9-26,$ write each expr…

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So you want to write The expression is product that soon. Bye. No meals. So the first step is to look at our first sermon Multiply bar last time. So two times negative three gives us negative six. So you know what? It's a multiplier. Get native six And then we look at our middle term, which is positive by and we want them to add to the positive five. So we do this to split apart this middle term here so that we get factor by grouping Go. We need four terms. So you were at the factors of one in six and then two and three. And we know that one of these hat one of these in the pier has to be negative because we have a negative six here. So for insists, if it was the first pair, this would have to be negative or this happy negative would not vote in it and one of them has to be negative. So now we need to look and which pier, which which combination will give us positive by so just looking and doing the lunch combinations? We know that if we have negative one and positive six that would add to positive by. So now we need to split apart are five wide. So have to r squared. And then we have minus Why? Well, one y close six. Why? And then minus three, the now needs to group that mercy terms and group the last two terms. And we need to pull out the greatest call me factor or the greatest Conan Malone. You so from the Priceline, we don't have any regular numbers to pull out, But we can't pull out this. Why? Of the lowest degree. So we're gonna pull out. Why it? We're left with two. Why? Minus one on the inside. And you can always check your stuff are redistributing it back. And then from the 2nd 1 we're gonna pull out a three that we don't have any very well supply route. So we just pull out three every left with to ah, minus one. So you know you're on the right path when you have the same term here in the same term here. So we bring that down to arm on this point and then whatever. We're left with five plus three

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