Question

In a $100 \mathrm{~m}$ race, Akbar gives Birbal a start of 2 seconds. Birlbal covers $10 \mathrm{~m}$ by the time Akbar starts. If both of them finish together, find Akbar's speed. (in $\mathrm{m} / \mathrm{sec}$ ) (A) 5 (B) $5 \frac{5}{9}$ (C) $4 \frac{1}{2}$ (D) 4

Name: Problem 12, Chapter 2: Computer Science and Information Technology
Uploaded: 2022-01-09T15:00:36-08:00
Duration: 3 min 11 s
Channel: Vishal Gupta
Description: In a 100 m race, Akbar gives Birbal a start of 2 seconds. Birlbal covers 10 m by the time Akbar starts. If both of them finish together, find Akbar's speed. (in m / sec ) (A) 5 (B) 5 (5)/(9) (C) 4 (1)/(2) (D) 4

   In a $100 \mathrm{~m}$ race, Akbar gives Birbal a start of 2 seconds. Birlbal covers $10 \mathrm{~m}$ by the time Akbar starts. If both of them finish together, find Akbar's speed. (in $\mathrm{m} / \mathrm{sec}$ )
(A) 5
(B) $5 \frac{5}{9}$
(C) $4 \frac{1}{2}$
(D) 4

Computer Science and Information Technology

Trishna Knowledge… 2018 Edition

Chapter 2, Problem 12

Instant Answer

Solved by Expert Vishal Gupta

01/09/2022

Step 1

Given that Birbal covers 10 m in 2 seconds, we can use the formula for speed which is distance/time. So, the speed of Birbal (V_B) is 10 m / 2 s = 5 m/s. Show more…

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In a $100 \mathrm{~m}$ race, Akbar gives Birbal a start of 2 seconds. Birlbal covers $10 \mathrm{~m}$ by the time Akbar starts. If both of them finish together, find Akbar's speed. (in $\mathrm{m} / \mathrm{sec}$ ) (A) 5 (B) $5 \frac{5}{9}$ (C) $4 \frac{1}{2}$ (D) 4

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Key Concepts

Uniform Motion

Uniform motion refers to movement at a constant speed, where the distance traveled is directly proportional to the time elapsed. This principle is central to problems involving objects moving along a straight path with no acceleration, allowing the use of the formula distance = speed × time.

Time Head Start

A time head start is the advantage given to one competitor by allowing them to begin moving before another. This concept is crucial in setting up comparisons of travel times and distances for both competitors, enabling the formation of equations that account for this delay.

Simultaneous Finish Condition

The simultaneous finish condition occurs when two competitors finish a race at the same time, despite differences in their start times or speeds. This condition is used to equate the time taken by each competitor after accounting for any head starts, forming the basis of solving for unknown speeds or distances.

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