in-a-certain-region-about-6-of-a-citys-population-moves-to-the-surrounding-suburbs-each-year-and-abo

Question

In a certain region, about 6% of a city’s population moves to the surrounding suburbs each year, and about 4% of the suburban population moves into the city. In 2015, there were 10,000,000 residents in the city and 800,000 in the suburbs. Set up a difference equation that describes this situation, where $\mathbf{x}_{0}$ is the initial population in 2015 . Then estimate the populations in the city and in the suburbs two years later, in 2017 .

Jack Chen · Accepted Answer

Okay, So in this problem, um, we want to set up a difference equation. Except K plus one equals two. A tradition may metrics and times, except K. I&#x27;m so for each x sub k. The first entrance, the population in the city, the second change the population in the surrounding area and the full transition metrics the engine will be so because we defied our, um, they were bring this way. So for the transition metrics on the frosting trim, we will be the people stay, you see. And the second you will be the people move from the surrounding area. Two of those et the 30 into it will be the people move from the city to the surrounding area. The last intern will be the people, um, stay Penis around the area. Okay, so you if we if we understand this, those legit geometrics in this case will be your night. 0.94 You&#x27;re going 04 to open 06 and the 0.96 So this state eyes are given in the problem. We just need toe Rearrange this in the correct order in the initial state eg zero will be, um so that would be 10 million and uh, 100,000. Okay, so we are looking for, um after two years, with the population in the city and the water population in the surrounding area, that would be x two extra, because to end times X one, which is in terms in tans x zero. So bad calculator you will be a foreign result. So this is the solution to this.

Trinity Steen · Answer

Okay, So for this problem, it&#x27;s talking about a 10% chance of males having a color perception defect when they&#x27;re borns like color blindness. So if we&#x27;re talking about 10 out of 100 or 10% and I use the double digits 00209 as an assignment, we&#x27;re going to let 0009 Rep. I resent the color her exception defect, and then we&#x27;ll let 10 toe 99 represent no defect. And then we can run a random number simulation and do each trials digit numbers we get. If we get the number 0009 that means that person had a color perception defect trial. And then if we get 10 to 99 then that means that person head of these that I would just keep recording until we go through. However, many trials at least 20 toe 100 miles of the better

William Scherer · Answer

Okay, so these are the three formulas will be using for the mean it&#x27;s end times p for the standard deviation. It&#x27;s the square root of N. P. Q. And for the Z score, it&#x27;s X minus the mean divided by the standard deviation. Okay, we need this table for the continuity correction factor. Yeah, so on number nine, we have p equals 22% which is 220.22 And we have n equals 200. All right, so for our mean, it&#x27;s just end times p. So 200 times 2000.22 is going to give us 44. Our standard deviation is the square root of end times P, which is 44 times Q, which is one minus p. All right, on the calculator, that&#x27;s going to give us 5.86 Just round to two decimals, if you need to. All right. And we want to find the probability that X is greater than 30. Okay. And for our continuity correction, as you can see right here, you have to add 0.5. Okay, so we&#x27;re gonna add 0.5 to 30 and we want to find the probability that X is greater than 30.5. All right, so that 30.5 is gonna be our new X value. So for the Z score for the Z score formula is X minus the mean, which is 44 divided by the standard deviation, which is 5.86 Okay, now this will give us negative 2.30 Okay, around 22 desperate places if you need to. And when you look up this Z score on the table, you should get 0.107 Okay, now, that&#x27;s the probability that X is less than 30.5. Okay, So in order to find greater than 30.5, we have to subtract that value that we just got from one. So one minus 0.107 is gonna give us 0.9893 And to convert that to decimal, you just move the desperate place over two places. So that&#x27;s 98.93 percent. Yeah,

William Scherer · Answer

Okay, this is for problem number 10. We have n equals 500 and we have p equals 56%. When you convert that to decimal, it&#x27;s 0.56 Okay, Our standard deviation is end times P. So 500 times 5000.56 it&#x27;s gonna give us 280. Okay. Our standard deviation is N P. Q. We already said NP was to 80 and cue is just one minus p, and that equals 11.10 Okay, around to one decimal, two decimal places if you need to. And we want to find the probability that X is greater than or equal to 250. Now we go to the table for for our continuity correction factor. Okay, When it&#x27;s greater than or equal to, you have to subtract 0.5 and remove the equal sign. All right, so this becomes the probability that X is greater than to 49.5. Okay, you just you just subtract 0.5 from 2 50 and remove the equal sign. So that&#x27;s gonna be our new X value. When we find the Z score. So Z equals X, which is to 49.5, minus the mean, which is to 80 divided by the standard deviation. Okay. And that is going to give us negative 2.75 All right, round to two decimal places, if you need to. You have to look up negative. 2.75 on the Z score table. OK? And when you do that, you will get a value of point 0030 Okay, now, that&#x27;s the probability that X is less than 2 49.5 but we need it for greater than Okay. So in order to do that, you just subtract this value from one. Okay, So do one minus 0.30 Okay. And that gives us point 9970 All right. And to convert that to percentage, just move the decimal place over two places, so we get 99 0.70%

Bon Zapata · Answer

So this problem wants us to find the Nolan alternative hypothesis to this claim. 42% of Fisher female, but we&#x27;re starting the think that it&#x27;s actually lower. So the way we right No. One alternative hypothesis is with an H Oh, that this means no hypothesis and h a means alternative hypothesis. So how do we know which one is which? The alternative hypothesis is usually what the researcher is claiming, or it means there&#x27;s a difference between two groups or a difference between a population in the sample. The null hypothesis is the opposite. It&#x27;s usually what the researcher isn&#x27;t trying to claim, or it means there&#x27;s no difference between two groups or population and sample. So in this problem, you want to test to see if that number is actually lower. So the alternative hypothesis will be that P is less than point for two. Or you could write 42%. Then the Noi pop Asus will be everything else. Probability is greater than or equal to point for two. We need to make sure to include that equal to option because we have to include every possibility here and we are done

Tate Hilken · Answer

the average conditions oven area can be defined as climate climate is typically a 30 year average of the weather averaged out in a specific area, and that is that 30 year average that defines a client. And some climates can be very warm and sunny, like in Arizona. Or some climates can be very moderate, too cold. For example. In Maine, climates are the average of larger area, or average of a region, rather than they are less subject to very rapid change, such as weather conditions.

Problem

In 2012 the population of California was 38,041,4…

Problem 10 Easy Difficulty

Answer

(a) $\left[\begin{array}{ll}{0.94} & {0.04} \\ {0.06} & {0.96}\end{array}\right] \mathbf{x}_{k}=\mathbf{x}_{k+1}$
(b) $\left[\begin{array}{l}{8920800} \\ {1879200}\end{array}\right]$

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David C. Lay, Steven R. Lay, Judi J. McDonald

Linear Algebra and Its Applications

Anna Marie V.

Heather Z.

Caleb E.

Kristen K.

Absolute Value - Example 1

Absolute Value - Example 2

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(a) $\left[\begin{array}{ll}{0.94} & {0.04} \\ {0.06} & {0.96}\end{array}\right] \mathbf{x}_{k}=\mathbf{x}_{k+1}$(b) $\left[\begin{array}{l}{8920800} \\ {1879200}\end{array}\right]$

Linear Algebra and Its Applications

Anna Marie V.

Heather Z.

Caleb E.

Kristen K.

Absolute Value - Example 1

Absolute Value - Example 2

David C. Lay, Steven R. Lay, Judi J. McDonaldLinear Algebra and Its Applications

Anna Marie V.

Heather Z.

Caleb E.

Kristen K.

(a) $\left[\begin{array}{ll}{0.94} & {0.04} \\ {0.06} & {0.96}\end{array}\right] \mathbf{x}_{k}=\mathbf{x}_{k+1}$
(b) $\left[\begin{array}{l}{8920800} \\ {1879200}\end{array}\right]$

David C. Lay, Steven R. Lay, Judi J. McDonald

Linear Algebra and Its Applications