00:01
So for part a, as the loop falls out of the magnetic field, the flux through the loop decreases with time, creating an induced emf in the loop.
00:10
And the current in the loop is equal to the emf divided by the resistance, which can be written in terms of the resistivity using equation 25 .3.
00:20
So i is equal to, which is equal to pi d squared divided by 4 over.
00:30
So d, b over dt, and that's equal to pi d squared over 16 times b, d -a -d -t, which is equal to pi -d -squared over 16 pl, so this current induces a force on the three sides of the loop in the magnetic field.
01:08
The forces on the two vertical sides are equal and opposite and therefore cancel out.
01:13
So f equals i, l, b, and that's equal to pi d squared over 16 pls times b, lv, l, and that's equal to pi d squared, b squared, lv, over 16ps...