00:02
In this problem, there are eight women, 11 men, and we're going to find the number of five member committees.
00:09
And when you see the word committee, basically it's a group of people where the order doesn't matter.
00:14
So we're looking at combinations here.
00:19
So the first one, if it's all women, that means there are five women.
00:23
So out of a total of eight women, we're choosing five.
00:26
And then if we put that in a calculator or compute it using the combination formula, we end up with 56.
00:33
For part b, the committee has all men, so that would be five men out of a total of 11 men, so that's 11, c, 5, and that works out to be 462.
00:46
For part c, there are three women and two men.
00:49
So for the three women part, we have 8, c3, and for the two men, we have 11, c2, and we multiply these because of the fundamental counting principle.
00:59
We have women, and we have men, and when it's and, you multiply the number of out.
01:04
Outcomes.
01:05
So 8c3 is 56 and 11c2 is 55.
01:11
So we multiply those together and we get 3 ,080...