00:01
In a compound microscope, the focal length of the objective is 3 .5 centimeters and that of the eye piece is 6 .5 centimeters.
00:08
The distance between the lenses is 26 centimeters.
00:11
What is the angular magnification of the microscope if the person using it has a near point of 35 centimeters? if, as usual, the first image lies just inside the focal point of the eye piece, how far is the object from the objective? what is the magnification? not the angular magnification.
00:30
Of the objective.
00:33
Okay, so starting this off, the angular magnification of a microscope is given by n is equal to negative l minus f .e times n over fo times fe.
00:51
So we are given the values here l is 26 centimeters, f .e is 6 .5.
01:03
N is 35.
01:07
And then we have 3 .5 times 6 .5.
01:13
So just to go through this in a little bit more detail, l is 26 centimeters, because that's the distance between the lenses.
01:24
N is the near point, so that's 35 centimeters.
01:27
And then f .e is the focal length of the eye piece...