Question
In a cyclotron (one type of particle accelerator), a deuteron (of mass 2.00 u) reaches a final speed of 10.0$\%$ of the speed of light while moving in a circular path of radius 0.480 $\mathrm{m}$ . The deuteron is maintained in the circular path by a magnetic force. What magnitude of force is required?
Step 1
The conversion factor is 1.66 x 10^-27 kg/u. So, the mass of the deuteron in kilograms is: \[m = 2.00 \, u \times 1.66 \times 10^{-27} \, kg/u = 3.32 \times 10^{-27} \, kg\] Show more…
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In a cyclotron (one type of particle accelerator), a deuteron (of atomic mass 2.00 $\mathrm{u}$ ) reaches a final speed of 10.0$\%$ of the speed of light while moving in a circular path of radius 0.480 $\mathrm{m}$ . The deuteron is maintained in the circular path by a magnetic force. What magnitude of force is required?
In a cyclotron (one type of particle accelerator), a deuteron (of mass 2.00 u) reaches a final speed of 10.0% of the speed of light while moving in a circular path of radius 0.480 m. What magnitude of magnetic force is required to maintain the deuteron in a circular path?
In a cyclotron (one type of particle accelerator), a deuteron (of mass 2.00 u) reaches a final speed of $10.0 \%$ of the speed of light while moving in a circular path of radius $0.480 \mathrm{~m}$. What magnitude of magnetic force is required to maintain the deuteron in a circular path?
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