00:01
In the given problem, effective resistance through which the capacitor discharges in defibrillator is given as r is equal to 52 .0.
00:43
Now in the first part of the problem we have to find the maximum potential.
00:53
So as the maximum current given is maximum current passing through the capacitor is i0 is equal to using home slow that should be given as i not is equal to v0 by r and this maximum current is given as 40 .0 ampere hence v0 will be given by i not into r so this is 40 .0 ampere multiplied by 52 .0 0 om so this maximum potential applied is 2 ,080 volt which is the answer for the first part of this problem.
01:43
Now, in the second part of the problem, the time given is 1 .00 milliseconds in which the current drops to 10 .0 ampere.
02:01
So, using the equation of current in a discharging capacitor, which is given as i is equal to i -0, into e -raged to the power minus t by tau, where tau is the time constant of cr circuit.
02:46
So here this i is 10 .0 a .mper.
02:50
I know it was 40 .0 ampere.
02:53
E -raged to the power minus t, which is given as 1 .00 milliseconds divided by time constant tau, which is missing.
03:02
So canceling this, we get e -raged -to -the -power minus 1 .00.
03:08
Millisecond divided by tau is equal to 0 .25...