In a $\Delta \mathrm{PQR}, \mathrm{M}$ lies on $\mathrm{PR}$ and between $\mathrm{P}$ and $\mathrm{R}$ such that $\mathrm{QR}=\mathrm{QM}=\mathrm{PM}$. If $\angle \mathrm{MQR}=40^{\circ}$, then find $\angle P$.
(1) $35^{\circ}$
(2) $25^{\circ}$
(3) $45^{\circ}$
(4) $55^{\circ}$