00:01
So first we have a distribution of scores x equals 64 corresponds to z equals 1.
00:06
That gives us 1 equals 64 minus y over x.
00:11
And then we have and x equals 67 corresponds to z equals 2.
00:17
That gives us 2 equals 67 minus y over x.
00:23
Now i have two unknowns and two equations and we can use algebra to solve this.
00:29
I'm going to start with the 1 equals 64 minus y over x.
00:32
And i'm going to solve this for x.
00:34
I'm going to multiply both sides by x.
00:37
So we get 1 times x which is just x equals 64 minus y.
00:43
I'm going to go over here and i'm going to, i just want to get rid of the fraction.
00:49
I don't want to deal with it.
00:50
So i'm going to multiply both sides by x.
00:53
X times 2 is 2x equals 67 minus y...