In a fermentation unit, glucose (C6 H12 O6) undergoes fermentation in the presence of yeast to p

In a fermentation unit, glucose (C6 H12 O6) undergoes...

In a fermentation unit, glucose $\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)$ undergoes fermentation in the presence of yeast to produce ethanol $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)$ and carbon dioxide $\left(\mathrm{CO}_{2}\right) .(7.6,7.7)$ a. How many grams of glucose are required to form $200 \mathrm{~g}$ of ethanol? b. How many grams of ethanol would be formed from the reaction of $0.320 \mathrm{~kg}$ of glucose?

In a fermentation unit, glucose $\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)$ undergoes fermentation in the presence of yeast to produce ethanol $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)$ and carbon dioxide $\left(\mathrm{CO}_{2}\right) .(7.6,7.7)$
a. How many grams of glucose are required to form $200 \mathrm{~g}$ of ethanol?
b. How many grams of ethanol would be formed from the reaction of $0.320 \mathrm{~kg}$ of glucose?

Key Concepts

Balanced Chemical Equation

A balanced chemical equation is a representation of a chemical reaction where the number of atoms for each element is the same on both the reactant and product sides. This ensures the law of conservation of mass is satisfied and provides the stoichiometric ratios necessary for quantitative calculations between the reactants and products.

Mole Concept

The mole concept is a fundamental principle in chemistry used to relate the mass of a substance to the number of particles it contains. It allows chemists to convert between grams and moles using Avogadro's number, enabling accurate quantitative analysis in chemical reactions.

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole. It is calculated by summing the atomic masses of all atoms in a molecule, and it is essential for converting between the mass of a substance and the number of moles present.

Stoichiometric Calculations

Stoichiometric calculations involve using the mole ratios derived from a balanced chemical equation to determine the proportional relationships between reactants and products. This process facilitates the conversion from the mass of one substance to the mass of another, ensuring that the law of conservation of mass is maintained in quantitative reaction analyses.

Transcript

00:01 In a fermentation unit, glucose or c6h12o6 undergoes fermentation to produce ethanol or c2h5oh and carbon dioxide.

00:17 How many grams of glucose are required to form 200 grams of ethanol, and how many grams of ethanol would be formed from a reaction of 0 .320 kilograms of glucose? so x grams.

00:34 So we have two problems here, a and b.

00:37 First, let's take a look at this equation and balance it.

00:40 Notice that we have six carbons on the left and three on the right, so we're going to need to add some values to the right.

00:46 In fact, all we're going to need to do is add a 2 and a 2.

00:50 So a 2 in front of the ethanol and a 2 in front of the carbon dioxide.

00:54 Now, let's get some molar masses out of the way, because we're going to be using these quite a bit.

00:59 And then we have carbon dioxide.

01:05 So let's scroll over a little bit.

01:07 Here we have our sucrose.

01:10 That's going to be 6 times 12 .01 plus 12 times 1 .008 plus 6 times roughly 16.

01:20 So this is going to come out to be 180 .16, and the units are grams per mole.

01:27 Now for ethanol, we have 2 times 12 .01 plus 5 times 1 .008 plus 16 plus 1 .008.

01:41 So that comes out to be 46 .07 grams per mole.

01:47 Carbon dioxide, well, that's 12 .01 plus 2 times 16.

01:52 So that comes out to be 44 .01 grams per mole.

01:57 Great.

01:59 So now let's go back to our equations.

02:02 Let's start with a.

02:04 Here we're starting with 200 grams of ethanol, and i'm going to shorten that to e.

02:09 From here, we need to convert to moles.

02:11 So 1 mole over 46 .07 grams...

Please give Ace some feedback