00:01
So this is a multi -part problem and we're thinking about the supply and demand and how they both depend on price.
00:09
So we're given these two equations and they both relate these variables p and d.
00:14
In this first equation, this is about the demand and demand is based on price.
00:19
So d stands for demand and that'll change based on the price going up or down.
00:24
In the second equation, d is standing for supply and p is the price.
00:29
So suppliers will only make a certain amount if they have a certain price that they're working with.
00:36
And d means two things, but it's given by the same variable because it actually will mean the same thing when we get to part b of this, because we'll be looking for an equilibrium point.
00:47
So first, though, we have to solve for when supply is going to be greater than zero.
00:54
So we have to find what's the minimum price at which manufacturers are going to start supplying.
01:00
Oil.
01:01
If the price isn't high enough, there's not going to be any supply because they won't be making it out of money.
01:06
So we need to take the second equation and we need to find the price p that gets d higher than zero.
01:15
So to do that, we are going to set d equal to zero and solve and then we'll round up to the next to nearest cent.
01:23
So we'll set d equal to zero.
01:27
So we're doing 8p squared minus 8p minus 0, so we don't need to rate it equals 12.
01:36
And so we have a quadratic that we got to solve.
01:39
So 8p squared minus 8p minus 12 equals 0.
01:44
We subtract 12, so we can factor, if we can factor, or we can have our a, b, and c ready to go into the quadratic formula.
01:53
This does not factor, so we're going to use the quadratic formula.
01:56
X equals 8 plus or minus the square root of negative 8 squared which is 64 minus 4 times 8 times negative 12 and that's all over 16 and so we'll use a calculator for this because it's not rational we don't need a graph and calculator just a basic calculator we'll do so we get x equals 8 plus or minus the square root of 448 and so we might have up to two solutions here because we have the plus or minus option.
02:33
So the first option is x equals 1 .82 for the plus option and then the minus option is x equals negative 0 .822.
02:49
We're going to reject this solution because this is a negative price and that's not in the domain of this problem.
02:57
So though it is a solution to the quadratic, it's not actually.
02:59
A solution to this real world application -based problem.
03:03
So this is not a solution that's going to work for us.
03:06
This, however, is.
03:08
And so this is saying at $1 .82, they're not going to be making anything.
03:15
But if we raised this, if we rounded up to the next nearest cents, so $1 .83, that's when demand starts.
03:25
So this is the lowest minimum price for oil that menu.
03:29
Manufacturers will start making.
03:32
Okay, so that's the solution to our first part a.
03:35
We've got the price, the minimum price, that oil production will start at.
03:40
Now let's move on to part b.
03:44
So in part b, we're asked to use a system to find the equilibrium point.
03:49
And the system we're using is the system of two equations that's given at the beginning.
03:54
Nothing's different except for d means the same thing.
03:58
D means both supply and demand, but equilibrium is when supply equals demand.
04:05
So now d is just one variable.
04:07
It just stands for oil, what's the unit here? it stands for 10 ,000 of gallons of oil in the marketplace.
04:15
It's the same variable.
04:17
So we have to go about solving the system now for both p and d.
04:22
We need to find the price at which we'll have equilibrium, and also how much oil will be in the marketplace at that point.
04:29
Point.
04:31
So to solve this system, we can go about it a few different ways...