In a fuel cell methanol is used as fuel and oxygen gas is used as an oxidizer. The reaction is
$$
\mathrm{CH}_3 \mathrm{OH}(\mathrm{l})+3 / 2 \mathrm{O}_2(\mathrm{~g}) \longrightarrow \mathrm{CO}_2(\mathrm{~g})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{l})
$$
At 298 K standard Gibb's energies of formation for $\mathrm{CH}_3 \mathrm{OH}$ (1), $\mathrm{H}_2 \mathrm{O}$ (1) and $\mathrm{CO}_2$ (g) are $-166.2 .-237.2$ and $-394.4 \mathrm{kJmol}^{-1}$ respectively. If standard enthalpy of combustion of methanol is $-7269 \mathrm{~kJ} \mathrm{~mol}^{-1}$, efficiency of the fuel cell will be:
[2009]
(a) $87 \%$
(b) $90 \%$
(c) $97 \%$
(d) $80 \%$