00:01
Okay, this is a problem where they tell us the angle of direction and the magnitude of the speed for a forward bounce pass, which is a pass where the basketball is intentionally shot at the floor.
00:14
My diagram here is that this angle is 15 degrees, and it's passed with the speed of 4 .3 meters per second.
00:25
So here, the first thing to do is solve for the time in the air.
00:31
That's what i like to do first.
00:32
The first thing to do that, i'm going to use the position equation for y, which is that zero, which is the final position on the ground, is going to equal the original position, that 0 .8, plus v -i initial in the y direction, times time, plus b -i initial.
00:55
One half gravity t squared.
01:00
And i'm just going to label this as the y position here to keep my numbers and equations at the same stage.
01:07
Okay, so i just have to solve for this.
01:10
I have to calculate this.
01:12
That's v initial y is always equal to, that's the velocity total times sign of the angle, or 15 here.
01:21
And that is equal to 1 .11 meters per second...