00:01
All right, we have a problem with a rolling or spinning cylinder, and the problem gives us the position of the roller according to its angle measure and with respect to time.
00:23
All right, then it asks us for the maximum angular speed.
00:28
Now, if it's asking us for speed or rate of change, then we know we need to take the derivative.
00:37
So we're taking the derivative of the angular position with respect to time, and that will give us the angular speed radiance per second.
00:47
It is a cubic polynomial.
00:51
It's pretty straightforward to take the derivative.
00:54
You take the coefficient, multiply it by the exponent, and subtract.
00:59
The exponent by 1.
01:01
So 2 .5 times 2 is 5 and 2 minus 1 is 1.
01:08
So 5t.
01:10
And then the other term, same thing.
01:12
0 .6 times 3 is 1 .8.
01:16
3 minus 1 is 2.
01:19
So 2 to the second power.
01:21
This is the angular speed radiance per second.
01:27
Now, it would like to know what the maximum angular speed is.
01:35
Well, this is a quadratic function.
01:40
The leading coefficient is a negative 1 .8, so it is a quadratic function that opens down.
01:48
Looks like an upside down to you.
01:49
If we put zero in for time, you will notice that you get zero, zero minus zero.
01:57
So at time zero, the cylinder is not moving.
02:03
No, angular speeds.
02:04
Angular speed is zero.
02:06
If we would like the maximum angular speed, which is what this axis is there, we would like this point right here.
02:15
Now this point here has a slope.
02:17
If you draw on the tangent line, you will see the slope.
02:20
The slope is zero.
02:23
Slope equals zero.
02:25
If we want to, so that's where the maximum is, is when the slope of the tangent line is zero.
02:32
You may have heard these words before.
02:34
They should ring bells.
02:35
It says, take the derivative.
02:38
All right.
02:38
So if we take the derivative of this quadratic function, said it equal to zero, we should have the time for the maximum speed.
02:47
So zero equals, take the derivative same way.
02:50
Five times one is five.
02:53
T to 1 minus 1.
02:55
T to the 0 power.
02:57
Anything to the 0 power is 1.
02:59
5 times 1 is 5 .1 .8 times 2 and then 2 minus 1 is 1.
03:09
So this is what we have.
03:11
And look at that.
03:11
We have t so we can find t.
03:13
We subtract 5 from both sides.
03:17
All right...